Answer:
16
Explanation:
FIRST AND FOREMOST, BALANCE YOUR EQUATION.
Al + S8 ➡️ Al2S3
Numbers of Al=1. ➡️ Numbers of Al = 2
Numbers of S =8. ➡️ Numbers of S. = 3
USE COEFFICIENT TO BALANCE THE EQUATION.
16Al + 3S8 ➡️ 8Al2S3
Now the Numbers of Al and S in both sides of eqn. is balanced
The Answer Is 16
For the basic solution:
11.2 = -log[H+]
[H+] = 6.31 x 10⁻¹²
For the acidic solution:
2.4 = -log[H+]
[H+] = 3.98 x 10⁻³
The difference:
3.98 x 10⁻³ - 6.31 x 10⁻¹²
≈ 4.0 x 10⁻³
The answer is B
<em>Calculate the molar fraction of NaClO in a commercial bleach solution that contains 3.62% by mass of NaClO in water</em>
<em />
<h3>Further explanation</h3>
convert mass to mol
mol NaClO (MW=74.5 g/mol) :
mol H₂O (MW= 18 g/mol) :
Total mol :
0.0486 + 5.354 = 5.4026
mol fraction of NaClO :
<span> Magnesium chloride is the answer to this question
</span>
Answer:
+6
Explanation:
We are given;
We are required to determine the oxidation number of S in the compound.
We need to know that;
- The total oxidation number of this compound is Zero
- Oxidation number of Ba metal is +2
- Oxidation number of Oxygen atom is -2
- There is 1 atom of Ba, 1 atom of S and 4 atoms of O in the compound.
Therefore; assuming oxidation number of S is x
Then, (1× 2) + (1 × x) + ( 4 ×(-2)) = 0
2 + x - 8 = 0
x = 6 or +6
Thus oxidation number of Sulfur in BaSO₄ is +6.
