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den301095 [7]
3 years ago
5

Did diagram shows embryo development of four different animals. How is this evidence used to suggest that life changes over time

Chemistry
2 answers:
TEA [102]3 years ago
8 0

Helloooo,

I know im late but anyone else taking the test now the answer would be.

<u><em>B-</em></u>

<em>In the early stages of embryonic development, these four vertebrates are quite similar, indicating a possible common ancestor.</em>

wel3 years ago
5 0
It suggests that life changes over time by showing different animals at different stages in their life, also giving more than one example on how they can change during early development and throughout their lives
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Balance the following redox equation using the smallest integers possible and select the correct coefficient for the hydrogen su
goldfiish [28.3K]

Answer:

Coefficient of HSO_{3}^{-} is 5

Explanation:

Oxidation: MnO_{4}^{-}(aq)\rightarrow Mn^{2+}(aq)

  • Balance O and H in acidic medium: MnO_{4}^{-}(aq)+8H^{+}(aq)\rightarrow Mn^{2+}(aq)+4H_{2}O(l)
  • Balance charge : MnO_{4}^{-}(aq)+8H^{+}(aq)+5e^{-}\rightarrow Mn^{2+}(aq)+4H_{2}O(l) .............(1)

Reduction: HSO_{3}^{-}\rightarrow SO_{4}^{2-}

  • Balance O and H in acidic medium : HSO_{3}^{-}(aq)+H_{2}O(l)\rightarrow SO_{4}^{2-}(aq)+3H^{+}(aq)
  • Balance charge : HSO_{3}^{-}(aq)+H_{2}O(l)-2e^{-}\rightarrow SO_{4}^{2-}(aq)+3H^{+}(aq) ..............(2)

[2\times eq(1)]+[5\times eq(2)] -

Balanced equation: 2MnO_{4}^{-}(aq)+5HSO_{3}^{-}(aq)+H^{+}(aq)\rightarrow 2Mn^{2+}(aq)+5SO_{4}^{2-}(aq)+3H_{2}O(l)

Coefficient of HSO_{3}^{-} is 5

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Mn(OH)2(s) + MnO4(aq) → MnO42–(aq) (basic solution) When the equation is balanced with smallest whole number coefficients, what
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Hi, the given equation has some missing parts. Actual equation is- 'Mn(OH)_{2}(s)+MnO_{4}^{-}(aq.)\rightarrow MnO_{4}^{2-}(aq.)'

balanced equation: Mn(OH)_{2}(s)+4MnO_{4}^{-}(aq.)+6OH^{-}(aq.)\rightarrow 5MnO_{4}^{2-}(aq.)+4H_{2}O(l)

Explanation:

Mn(OH)_{2}(s)\rightarrow MnO_{4}^{2-}(aq.)

Balance O and H in basic medium: Mn(OH)_{2}(s)+6OH^{-}(aq.)\rightarrow MnO_{4}^{2-}(aq.)+4H_{2}O(l)

Balance charge: Mn(OH)_{2}(s)+6OH^{-}(aq.)-4e^{-}\rightarrow MnO_{4}^{2-}(aq.)+4H_{2}O(l) ........(1)

MnO_{4}^{-}(aq.)\rightarrow MnO_{4}^{2-}(aq.)

Balance charge: MnO_{4}^{-}(aq.)+e^{-}\rightarrow MnO_{4}^{2-}(aq.) .....(2)

[equation(2)\times 4]+[equation (1)]:

Mn(OH)_{2}(s)+4MnO_{4}^{-}(aq.)+6OH^{-}(aq.)\rightarrow 5MnO_{4}^{2-}(aq.)+4H_{2}O(l)

OH^{-}(aq.) is present on the left hand side of balanced equation and it's coefficient is 6

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