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3 years ago

Daniel Ost’s acclaim is

Chemistry

1 answer:

Sholpan [36]3 years ago

3 0

Answer:

Daniel Ost is a Belgian floral artist, floral designer and garden architect. CBS News has described him as "the world's leading flower designer" while The New York Times says that "to call him a master flower designer is akin to calling Annie Leibovitz a shutterbug". His clientele includes numerous royal families, sheikhs, multinational organisations and humanitarian organisations like UNICEF.

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Convert the composition of the following alloy from atom percent to weight percent (a) 44.9 at% of silver, (b) 46.3 at% of gold,

vesna_86 [32]

Answer:

Mass percentage of gold : 33.35%

Mass percentage of silver: 62.80%

Mass percentage of copper : 3.85%

Explanation:

$N=n\times N_A$

Where : N = Number of atoms

n = moles

$N_A=6.022\times 10^{23}$ = Avogadro number

Let the total atoms present in the alloy be 100.

Atom percentage of silver = 44.9%

Atoms of of silver = 44.9% of 100 atoms = 44.9

Atomic weight of silver = 107.87 g/mol

Mass of 44.9 silver atoms = 107.87 g/mol × 44.9 = 4,843.363 g/mol

Atom percentage of gold= 46.3%

Atoms of of gold = 46.3% of 100 atoms = 46.3

Atomic weight of gold = 196.97 g/mol

Mass of 44.9 gold atoms = 196.97 g/mol × 46.3 = 9,119.711 g/mol

Atom percentage of copper = 8.8 %

Atoms of of copper = 8.8% of 100 atoms = 8.8

Atomic weight of copper = 63.55 g/mol

Mass of 44.9 copper atoms = 63.55 g/mol × 8.8 = 559.24 g/mol

Total mass of an alloy :4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol

Mass percentage of gold :

$\frac{4,843.363 g/mol}{4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol}\times 100=33.35 \%$

Mass percentage of silver:

$\frac{9,119.711 g/mol}{4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol}\times 100=62.80\%$

Mass percentage of copper :

$\frac{559.24 g/mol}{4,843.363 g/mol + 9,119.711 g/mol + 559.24 g/mol}\times 100=3.85\%$

7 0

3 years ago

3. What noble gas would be part of the electron configuration notation for Mn?

shusha [124]

Answer:

Argon {Ar}

Explanation:

The noble gas used for a condensed electron configuration is the one before the element which you are configuring.

In this case, the element (Mn) is manganese

The noble gas that is before this element is Argon which is the row above it

so your configuration would be {Ar} 3d^5 4s^2

7 0

3 years ago

Avogrados number of representatives particles is equal to one what?

kotykmax [81]

Answer:

Avogadro number of representatives particles is equal to one mole.

Explanation:

The number 6.022 × 10²³ is called Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

17 g of ammonia = 1 mole = 6.022 × 10²³ molecules of ammonia

12 g of carbon = 1 mole = 6.022 × 10²³ atoms of carbon

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

5 0

3 years ago

In a chemical reaction, ____ interact to form ____. select one:

QveST [7]

A. Reactants, products

In a chemical reaction, reactants interact to form products

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3 years ago

Which is the FALSE statement about C-14?

slega [8]

The answer is: A

C-14 is not stable and this is the reason why it goes through radioactive decay.

7 0

3 years ago

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