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2 years ago

Daniel Ost’s acclaim is

Chemistry

1 answer:

Sholpan [36]2 years ago

3 0

Answer:

Daniel Ost is a Belgian floral artist, floral designer and garden architect. CBS News has described him as "the world's leading flower designer" while The New York Times says that "to call him a master flower designer is akin to calling Annie Leibovitz a shutterbug". His clientele includes numerous royal families, sheikhs, multinational organisations and humanitarian organisations like UNICEF.

Hope this helps!

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A solution of copper sulfate (CuSO4) produced by bioleaching has a concentration of 0.319 g/dm3 Relative atomic masses (Ar): Cu

Tanya [424]

moles Cu produced : 0.002

<h3>Further explanation</h3>

Concentration of copper sulfate (CuSO₄) : 0.319 g/dm³

MW CuSO₄ :

$\tt =63.5+32+4\times 16=159.5~g/mol$

mol CuSO₄ /dm³ :

$\tt \dfrac{0.319}{159.5}=0.002$

CuSO₄⇒Cu²⁺ + SO₄²⁻

mol Cu : mol CuSO₄ = 1 : 1 , so mol Cu²⁺=0.002

6 0

2 years ago

Use the scenario to answer the following question. Four scientists observed an area of land that had been cleared of all trees a

Blizzard [7]

Answer:

Explanation:t not sure

3 0

3 years ago

Read 2 more answers

In an electroplating process, copper (ionic charge +2e, atomic weight 63.6 g/mol) is deposited using a current of 10.0 A. What m

salantis [7]

Answer : The mass of copper deposit is, 1.98 grams

Explanation :

First we have to calculate the charge.

Formula used : $Q=I\times t$

where,

Q = charge = ?

I = current = 10 A

t = time = 10 min = 600 sec (1 min = 60 sec)

Now put all the given values in this formula, we get

$Q=10A\times 600s=6000C$

Now we have to calculate the number of atoms deposited.

As, 1 atom require charge to deposited = $2\times (1.6\times 10^{-19})$

Number of atoms deposited = $\frac{(6000)}{2\times(1.6\times 10^{-19})}=1.875\times 10^{22}$ atoms

Now we have to calculate the number of moles deposited.

Number of moles deposited = $\frac{(1.875\times 10^{22})}{(6.022\times 10^{23})}=0.03113$ moles

Now we have to calculate the mass of copper deposited.

1 mole of Copper has mass = 63.5 g

Mass of Copper Deposited = $63.5\times 0.03113 =1.98g$

Therefore, the mass of copper deposit is, 1.98 grams

5 0

3 years ago

When 5.0 mol Al react with 13 mol HCl, what is the limiting reactant, and how many moles of AlCl3 can be formed? (2 points) 2Al

barxatty [35]

Well, we need to find the ratio of Al to the other reactant.

Al:HCl = 1:3

--> this means that for every 1 Al used, you have to use 3 HCl.

5*3 = 15 moles of HCl needed to fully react with 5 moles of Al. Since 13<15, HCL is the limiting reactant.

The ratio of HCl:AlCl = 3:1

13/3 = 4.3333...

The final answer is HCl is the limiting reactant with 4.3 moles of AlCl3 able to be produced so choice B.

Hope this helps!!! :)

5 0

3 years ago

A gas is collected in a 34.3L container at a temperature of 31.5°C. Later, the container has a volume of 29.2L, a temperature of

goldenfox [79]

Answer:

108 kPa

Step-by-step explanation:

To solve this problem, we can use the <em>Combined Gas Laws</em>:

p₁V₁/T₁ = p₂V₂/T₂ Multiply each side by T₁

p₁V₁ = p₂V₂ × T₁/T₂ Divide each side by V₁

p₁ = p₂ × V₂/V₁ × T₁/T₂

Data:

p₁ = ?; V₁ = 34.3 L; T₁ = 31.5 °C

p₂ = 122.2 kPa; V₂ = 29.2 L; T₂ = 21.0 °C

Calculations:

(a) Convert temperatures to <em>kelvins </em>

T₁ = (31.5 + 273.15) K = 304.65 K

T₂ = (21.0 + 273.15) K = 294.15 K

(b) Calculate the <em>pressure </em>

p₁ = 122.2 kPa × (29.2/34.3) × (304.65/294.15)

= 122.2 kPa × 0.8542 × 1.0357

= 108 kPa

4 0

3 years ago