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Otrada [13]
2 years ago
12

Daniel Ost’s acclaim is

Chemistry
1 answer:
Sholpan [36]2 years ago
3 0

Answer:

Daniel Ost is a Belgian floral artist, floral designer and garden architect. CBS News has described him as "the world's leading flower designer" while The New York Times says that "to call him a master flower designer is akin to calling Annie Leibovitz a shutterbug". His clientele includes numerous royal families, sheikhs, multinational organisations and humanitarian organisations like UNICEF.

Hope this helps!

You might be interested in
3. What is the energy of a photon whose frequency is 5.2 x 1015 Hz? Use the equation: E = hxv
anzhelika [568]

Answer:

3. 3.45×10¯¹⁸ J.

4. 1.25×10¹⁵ Hz.

Explanation:

3. Determination of the energy of the photon.

Frequency (v) = 5.2×10¹⁵ Hz

Planck's constant (h) = 6.626×10¯³⁴ Js

Energy (E) =?

The energy of the photon can be obtained by using the following formula:

E = hv

E = 6.626×10¯³⁴ × 5.2×10¹⁵

E = 3.45×10¯¹⁸ J

Thus, the energy of the photon is 3.45×10¯¹⁸ J

4. Determination of the frequency of the radiation.

Wavelength (λ) = 2.4×10¯⁵ cm

Velocity (c) = 3×10⁸ m/s

Frequency (v) =?

Next, we shall convert 2.4×10¯⁵ cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

2.4×10¯⁵ cm = 2.4×10¯⁵ cm × 1 m /100 cm

2.4×10¯⁵ cm = 2.4×10¯⁷ m

Thus, 2.4×10¯⁵ cm is equivalent to 2.4×10¯⁷ m

Finally, we shall determine the frequency of the radiation by using the following formula as illustrated below:

Wavelength (λ) = 2.4×10¯⁷ m

Velocity (c) = 3×10⁸ m/s

Frequency (v) =?

v = c / λ

v = 3×10⁸ / 2.4×10¯⁷

v = 1.25×10¹⁵ Hz

Thus, the frequency of the radiation is 1.25×10¹⁵ Hz.

8 0
2 years ago
Which objects cannot be observed in detail without a microscope?
Sonbull [250]

The objects which cannot be observed in detail without a microscope

include the following:

  • Red blood cell
  • Bacterium

<h3>What is a Microscope?</h3>

A microscope is an instrument which is used to view smaller objects such as

microbe,cells, tissues etc. This instrument is used in viewing the different

cells found in the body as they can't be seen with the eye.

The remaining options which can be seen with the eyes don't require

the use of microscopes.

Read more about Microscope here brainly.com/question/25268499

3 0
2 years ago
a sample of 3.00 g of so2 (g)originally in a 5.00 L vesselat 21 degee Celsius is transferred to a 10.0 L vessel at 26 degree Cel
eimsori [14]

Answer:

1) The partial pressure of SO₂ gas in the larger container = 0.115 atm.

2) The partial pressure of N₂ gas in the larger container = 0.206 atm.

3) The total pressure in the vessel = 0.321 atm.

Explanation:

  • To calculate the partial pressure of each gas, we can use the general law of ideal gas: PV = nRT.

where, P is the partial pressure of the gas in atm,

V is the volume of the vessel in L,

n is the no. of moles of the gas,

R is the general gas constant (R = 0.082 L.atm/mol.K),

T is the temperature of the gas in K.

<u><em>1) What is the partial pressure of SO₂ gas in the larger container?</em></u>

<em>∵ P = nRT/V.</em>

n = mass/molar mass = (3.0 g)/(64.066 g/mol) = 0.047 mol.

R = 0.082 L.atm/mol.K.

T = 26 °C + 273.15 = 299.15 K.

V = 10.0 L. (The volume of the new container)

∴ P = nRT/V = (0.047 mol)(0.082 L.atm/mol.K)(299.15 K)/(10.0 L) = 0.115 atm.

<u><em>2) What is the partial pressure of N₂ gas in the larger container?</em></u>

<em>∵ P = nRT/V.</em>

n = mass/molar mass = (2.35 g)/(28.0 g/mol) = 0.084 mol.

R = 0.082 L.atm/mol.K.

T = 26 °C + 273.15 = 299.15 K.

V = 10.0 L. (The volume of the new container)

∴ P = nRT/V = (0.084 mol)(0.082 L.atm/mol.K)(299.15 K)/(10.0 L) = 0.206 atm.

<u><em>3) What is the total pressure in the vessel?</em></u>

  • According to Dalton's law the total pressure exerted is equal to the sum of the partial pressures of the individual gases.

<em>∵ The total pressure in the vessel = the partial pressure of SO₂ + the partial pressure of N₂.</em>

∴ The total pressure in the vessel = 0.115 + 0.206 = 0.321 atm.

5 0
2 years ago
Describe how organisms in the tropical rainforest both depend on and compete for biotic and abiotic factors. In your answer, ide
nadezda [96]

What are biotic and abiotic factors?

Biotic and abiotic are the two essential factors responsible for shaping the ecosystem. The biotic factors refer to all the living beings present in an ecosystem, and the abiotic factors refer to all the non-living components like physical conditions (temperature, pH, humidity, salinity, sunlight, etc.) and chemical agents (different gases and mineral nutrients present in the air, water, soil, etc.) in an ecosystem. Therefore, both the abiotic and biotic resources affect the survival and reproduction process.

Answer:

Abiotic factors in the tropical rainforest include humidity, soil composition, temperature, and sunlight. A limiting factor in the ecosystem is that canopy layers block sunlight from reaching the forest floor, causing shorter plants to not be able to grow. Biotic factors in the tropical rainforest include orchids, lilies, heliconia, and bromeliads. Tropical rainforests can have various fungi, shrubs, herbs, woody vines, lichens, and mosses. The trees making up the rainforest canopy include the tonka bean wood, teak, rubber, and several species of evergreens and palm trees. This way the organisms in the tropical rainforest both depend on biotic and abiotic factors.

7 0
2 years ago
I need help answering this question
aleksandrvk [35]

Answer:

it is D

Explanation:

6 0
3 years ago
Read 2 more answers
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