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4 years ago

Use the equation

Chemistry

1 answer:

ratelena [41]4 years ago

5 0

(Answer) 39.77 g of copper (II) oxide would be formed from the complete reaction of 0.500 mol Cu.

Moles of Cu reacted = 0.500 mol

According to the balanced chemical equation, the mole ratio of copper and copper (II) oxide = 1: 1

Therefore, 0.500 moles of copper (II) oxide would be formed from the complete reaction of 0.500 mol Cu.

Mass of 0.500 moles of copper (II) oxide = (Number of moles x molar mass)

= (0.500 x 79.545) g = 39.77 g.

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Answer:

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Explanation:

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$90.0 s \times \frac{1s}{620c} \times \frac{96,468c}{1mole^{-} } \times \frac{3mole^{-}}{1molAl} \times \frac{26.98gAl}{1molAl} =1.13 \times 10^{6} g Al$

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4 years ago

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3 years ago

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