In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide Al2O3 dissolved in molten c
ryolite Na3AlF6, resulting in the reduction of the Al2O3 to pure aluminum. Suppose a current of 620.A is passed through a Hall-Heroult cell for 90.0 seconds. Calculate the mass of pure aluminum produced. Be sure your answer has a unit symbol and the correct number of significant digits.
<span>0.929 g/ml
Density in this case is defined as mass per volume. Or in other words, mass divided by volume. So you simply divide 929 grams by 1000 ml. Giving
929 g / 1000 ml = 929/1000 g/ml = 0.929 g/ml</span>