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nevsk [136]
3 years ago
6

Now let’s return to the question of why everything went off when the light, a heater, and a hair dryer were all running in the b

athroom at the same time. After all, the light usually stays on just fine whenever you use the bathroom. Why would it go off now?
Answer this question assuming the circuit breaker or fuse for the bathroom has a 40-ampere capacity. Use the terms “circuit,” and “overload.” Then think of at least two solutions to prevent this from happening again.
Chemistry
2 answers:
igomit [66]3 years ago
6 0

Answer:

The power must have gone out for that area.

Explanation:

erastova [34]3 years ago
3 0

Answer:

the amount of power went over the circuit breaker limit

Explanation:

The circuit breaker cut off everything in the bathroom because the limit was 40 amperes but the amount of power being used in the bathroom exceeded the limit, going up to 46.25 amperes. A way to stop this may be using an extension cord to plug in the hair dryer somewhere outside the bathroom while still being able to use it in the room, or instead of using the light in the bathroom, try using a night light or just light from outside the room that can still provide enough light in the bathroom.

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A voltaic cell is based on the following two half-reactions: ni 2(aq) 2e− → ni(s) e° = −0. 25 v cr 3(aq) 3e– → cr(s) e° = –0. 74
emmasim [6.3K]

The net cell reaction is given as 3 Ni²⁺ (aq) + 2 Cr (s) = 2 Cr³⁺ (aq) + 3 Ni (s), and the cell potential is 0.49 V.

<h3>What is a half-cell reaction?</h3>

A half cell reaction is given as the oxidation or the reduction reaction that takes place at each of the anode or the cathode, forming the net redox reaction.

The cell potential and the half-reactions are:

Ni²⁺ + 2e⁻ = Ni (s)     E° = -0.25 V

Cr³⁺ + 3e⁻ = Cr (s)     E° = -0.74 V

The anodic reaction is given as:

Cr (s) = Cr³⁺ + 3e⁻     E° = 0.74 V

The cathodic reaction is given as:

Ni²⁺ + 2e⁻ = Ni (s)     E° = -0.25 V

Thus, the net reaction of the cell will be:

3 Ni²⁺ (aq) + 2 Cr (s) = 2 Cr³⁺ (aq) + 3 Ni (s)

The cell potential can be calculated as:

E° = E (cathode) + E (anode)

E° = 0.74 + (-0.25) V

E° = 0.49 V

Thus, the net cell reaction is given as 3 Ni²⁺ (aq) + 2 Cr (s) = 2 Cr³⁺ (aq) + 3 Ni (s), and the cell potential is 0.49 V.

Learn more about cell potential, here:

brainly.com/question/1313684

#SPJ4

3 0
2 years ago
The radius of the large cylinder of a hydrolic press
Sloan [31]

Answer: 1) 400N

2)1.6

Explanation:

1) 5cm = 100N of force

so

20cm=400n

2) 0.4 X 4 = 1.6

3 0
3 years ago
How many grams of NH3 will have the same number of molecules as 26.2 g of C6H?
Effectus [21]

Answer: 2 grams

Explanation:

chemical formula of C6H:

C6H

relative atomic mass of

C:12

H:1

C6:72

H1:12

relative formula mass of

C6H1=73

molar mass of glucose:

73g

the molar mass is the mass of one mole of a substance.

in

26.2g

of C6H there are

26.2 divide by 73g moles present.

there are 0.358 or 35.8*10-1

I gram of NH3 is 17.03052

2 grams of NH3 is 35

3 0
4 years ago
Phosphofructokinase is a four‑subunit protein with four active sites. Phosphofructokinase catalyzes step 3 of glycolysis, conver
svp [43]

Answer:

1. PEP is a feedback inhibitor of phosphofructokinase.

4. PEP inhibition of phosphofructokinase yields a sigmoidal velocity versus substrate curve.

6. The binding of PEP to one phosphofructokinase subunit causes a conformation change that affects the ability of the substrate to bind to the other subunits.

Explanation:

Phosphofructokinase-1, PFK-1, is an allosteric enzymes composed of four protein subunits.

Allosteric enzymes are enzymes that function through non-covalent binding of allosteric modulators which may be activators or inhibitors. They produce a characteristic velocity versus substrate sigmoidal curve. PFK-1 has a separate binding site for its substrate, fructose-6-phosphate and it's allosteric modulators: ATP, ADP or phosphoenolpyruvate, PEP.

The enzyme can exist in two conformations, the T-state (tense) or the R-state (resting). Binding of substrate causes a conformational change from T-state to R-state, whereas binding of allosteric inhibitors returns it to the T-state.

PEP, the product of step 9 in glycolysis, is an allosteric inhibitor of PFK-1. When it binds to the the allosteric site, it leads to conformational changes in PFK-1 from the R-state to the T-state which reduces the enzymes ability to bind the substrate. These changes are responsible for the sigmoidal velocity/substrate curve in allosteric enzymes.

Therefore, the true statements from the options above are 1, 4, 6.

Options 2,3 and 5 are wrong because PEP is a negative effector of PFK-1, thus its binding reduces the affinity of PFK-1 for its substrate. Also, PFK-1 being an allosteric enzyme has separate binding sites for its substrate and its modulators. Thus, there is no competition for active site binding by substrate and modulators.

5 0
3 years ago
The chemical and mechanical breakdown of rock is called
nataly862011 [7]

Answer:

Weathering

Explanation:

can l be the brainliest

6 0
3 years ago
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