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4 years ago

Why do.we need inactive ingredients?

Chemistry

1 answer:

mel-nik [20]4 years ago

3 0

Answer:

Inactive ingredients are components of a drug product that do not increase or affect the therapeutic action of the active ingredient, which is usually the active drug. Inactive ingredients are added during the manufacturing process of pharmaceutical products such as tablets, capsules, suppositories, and injections

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__________ solutions are very unstable.

Serhud [2]

Answer:

none of the above

Explanation:

because all of them are unstable

3 0

3 years ago

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What is the “advantage” and “disadvantage” when there is a mechanical advantage less than 1?

tia_tia [17]

Answer: Force disadvantage and distance advantage

Explanation: When mechanical advantage is less than one the force of the strength decreases because input force is greater than output force.

The distance increases ie the object is moving over a long distance.

Example when fishing with a long fishing rod the force applied to move the fish from the water is greater than the weight of the fish itself. The advantage of using the long fishing pole is that the distance over which the fish travels is greatly increased.

Hope this helps. It took me about half an hour before I could get this answer from my various searches. The idea might not be clear but this was what I was able to understand.

5 0

3 years ago

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What is barium nitrate + sodium chromate

melamori03 [73]

Barium Nitrate = Ba(NO3)2
Sodium Chromate = (Na2CrO4)

Answer = BaCrO4+2NaNO3

6 0

4 years ago

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In the compound AbO3, the ratio of aluminum to oxygen is

jasenka [17]

The compound is Al2O3. The ratio of aluminum to oxygen is 2:3.

3 0

3 years ago

Methane and chlorine react to form four products: CH3Cl, CH2Cl2, CHCl3, and CCl4. At a particular temperature and pressure, 38.4

Anastasy [175]

Answer:

How many grams of CCL4 were formed? 116.9 g

How many grams of Cl2 reacted with the CH4? 243.8 g

Explanation:

First we need to know the molar mass for every element or compound in the reaction:

$M_{CH_{4}}=16 g/mol\\M_{CH_{3}Cl}=50.49g/mol\\M_{CH_{2}Cl_{2}}=84.93g/mol\\M_{CHCl_{3}}=119.38g/mol\\M_{CCl_{4}}=153.82g/mol$

Now we proceed to calculate the amount of moles produced, per product:

$n_{CH_{4}}=2.4\\n_{CH_{3}Cl}=0.18\\n_{CH_{2}Cl_{2}}=0.55\\n_{CHCl_{3}}=0.91\\n_{CCl_{4}}=n_{CH_{4}}-(n_{CH_{3}Cl}+n_{CH_{2}Cl_{2}}+n_{CHCl_{3}})\\n_{CCl_{4}}=0.76mol\\m_{CCl_{4}}=n_{CCl_{4}}*M_{CCl_{4}}\\m_{CCl_{4}}=116.9g$

To calculate the mass of chlorine we just need to make a mass balance:

$m_{CH_{4}}+m_{Cl_{2}}=m_{CH_{3}Cl}+m_{CH_{2}Cl_{2}}+m_{CHCl_{3}}+m_{CCl_{4}}\\m_{Cl_{2}}=m_{CH_{3}Cl}+m_{CH_{2}Cl_{2}}+m_{CHCl_{3}}+m_{CCl_{4}}-m_{CH_{4}}\\m_{Cl_{2}}=243.8g$

3 0

3 years ago