Answer:


Step-by-step explanation:
Let
x ---> the number
we know that
The algebraic expression is equal to multiply the number by 4, add 5 and equal 8
so

Solve for x
subtract 5 both sides

Divide by 4 both sides

<span>The quadrilateral ABCD have vertices at points A(-6,4), B(-6,6), C(-2,6) and D(-4,4).
</span>
<span>Translating 10 units down you get points A''(-6,-6), B''(-6,-4), C''(-2,-4) and D''(-4,-6).
</span>
Translaitng <span>8 units to the right you get points A'(2,-6), B'(2,-4), C'(6,-4) and D'(4,-6) that are exactly vertices of quadrilateral A'B'C'D'.
</span><span>
</span><span>Answer: correct choice is B.
</span>
Answer: 2(n + 4) (n - 4)
Step-by-step explanation:
Since both terms are perfect squares, factor using the difference of squares formula,
a^2 - b^2 = ( a + b ) ( a + b )
Answer: x= 8
Step-by-step explanation:
According to the converse of basic proportionality theorem,
If in ΔABC , DE is a line drawn from AB to AC such that 
then, DE is parallel to the third side BC.
Applying converse of basic proportionality theorem, to get NO parallel to KJ, we must have

Hence, the value of x should be 8, so that Line segment N O is parallel to line segment K J.