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jok3333 [9.3K]
3 years ago
5

Find the area A of polygon JKLMNO with the given vertices.

Mathematics
1 answer:
Naddika [18.5K]3 years ago
5 0

Answer:

Hey

Step-by-step explanation: ik you neeed hlep but no one is answering me question so... will someone come help meeee

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Match the verbal description to the correct expression.
dusya [7]

Answer:

1.    n + 34

2.   n - 34

3.   n × 34

Step-by-step explanation:

1. 34 more than a number     n + 34

2. a number decreased by 34      n - 34

3. the product of a number and 34    n × 34

6 0
3 years ago
8 (6× + 5) + 2× equivalent
Licemer1 [7]
8(6x + 5) + 2x
8(6x) + 8(5) + 2x
48x + 40 + 2x
50x + 40
5 0
3 years ago
What is 3/4 h = – 45/52
sergiy2304 [10]
Mixed number form: h = - 1 2/13 Hope that helps :))

6 0
3 years ago
The reference desk of a university library receives requests for assistance. Assume that a Poisson probability distribution with
NISA [10]

Answer:

a) 0.125

b) 7

c) 0.875 hr

d) 1 hr

e) 0.875

Step-by-step explanation:l

Given:

Arrival rate, λ = 7

Service rate, μ = 8

a) probability that no requests for assistance are in the system (system is idle).

Let's first find p.

a) ρ = λ/μ

\frac{7}{8} = 0.875

Probability that the system is idle =

1 - p

= 1 - 0.875

=0.125

probability that no requests for assistance are in the system is 0.125

b) average number of requests that will be waiting for service will be given as:

λ/(μ - λ)

= \frac{7}{8 - 7}

= 7

(c) Average time in minutes before service

= λ/[μ(μ - λ)]

= \frac{7}{8(8 - 7)}

= 0.875 hour

(d) average time at the reference desk in minutes.

Average time in the system js given as: 1/(μ - λ)

= \frac{1}{(8 - 7)}

= 1 hour

(e) Probability that a new arrival has to wait for service will be:

λ/μ =

{7}{8}

= 0.875

5 0
3 years ago
Function help please
Korvikt [17]

Answer:

The first table represents a function.

Step-by-step explanation:

For it to be a function, there needs to be 1 unique y value of 1 unique x value.

  • Looking at 2nd table, we see x value of -5 is mapped to 2 different y values of -5 and 5. So this is not a function.
  • Looking at 3rd table, we see x value of -2 is mapped to 2 different y values of 2 and 4. So this is not a function.
  • Looking at 4th table, we see x value of -4 is mapped to 2 different y values of 2 and 0. So this is not a function as well.

Looking at table 1, there are no duplicate x values and each of the 4 x values map to different values. So the first table represents a function.

4 0
3 years ago
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