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chubhunter [2.5K]
3 years ago
15

(-4,2) ;m=-1/3 You have to use this formula y=mx+b

Mathematics
1 answer:
svet-max [94.6K]3 years ago
7 0

Answer:

  y = -1/3x +2/3

Step-by-step explanation:

We assume you want the equation of the line through the given point. The point-slope form of the equation is a good place to start.

  y -k = m(x -h) . . . . . line with slope m through point (h, k)

  y -2 = -1/3(x +4) . . . . . . fill in given values

  y = -1/3x -4/3 +2 . . . . . eliminate parentheses, add 2

  y = -1/3x +2/3 . . . . . . . simplify

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Given a leading coefficient of 8, polynomial roots of 1 & 2, and the known point on the graph (4,5). Write an equation that
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Given:

The leading coefficient of a polynomial is 8.

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To find:

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Solution:

The factor form of a polynomial is:

y=a(x-c_1)(x-c_2)...(x-c_n)

Where, a is a constant and c_1,c_2,...,c_n are the roots of the polynomial.

Polynomial roots are 1 and 2. So, (x-1) and (x-2) are the factors of the polynomial.

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y=8(x-1)(x-2)(x-c)

The graph passes through the point (4,5). Putting x=4,y=5, we get

5=8(4-1)(4-2)(4-c)

5=8(3)(2)(4-c)

5=48(4-c)

Divide both sides by 48.

\dfrac{5}{48}=4-c

c=4-\dfrac{5}{48}

c=\dfrac{192-5}{48}

c=\dfrac{187}{48}

Therefore, the 3rd root on the polynomial is \dfrac{187}{48}.

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Step-by-step explanation:

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