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1 year ago

Uh need help

Mathematics

2 answers:

Kay [80]1 year ago

4 0

Answer:

$48

Step-by-step explanation:

the 4 part of the ratio refers to the original price of $64 , then

$64 ÷ 4 = $16 ← value of 1 part of the ratio , then

3 parts = 3 × $16 = $48 ← sale price

deff fn [24]1 year ago

3 0

Answer:

$48

Step-by-step explanation:

price of jacket : original price

3 : 4

If 64 = 4, we can find out 1.

64 / 4 = 16

16 x 3 = 48

16 x 4 = 64

48 : 64

sale price = $48

Hope this helps!

- profparis

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Questio

Olenka [21]

Answer:

d = -1/3, 0

Step-by-step explanation:

Subtract the constant on the left, take the square root, and solve from there.

(6d +1)^2 + 12 = 13 . . . . given

(6d +1)^2 = 1 . . . . . . . . . .subtract 12

6d +1 = ±√1 . . . . . . . . . . take the square root

6d = -1 ±1 . . . . . . . . . . . .subtract 1

d = (-1 ±1)/6 . . . . . . . . . . divide by 6

d = -1/3, 0

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Using a graphing calculator, it is often convenient to write the function so the solutions are at x-intercepts. Here, we can do that by subtracting 13 from both sides:

f(x) = (6x+1)^ +12 -13

We want to solve this for f(x)=0. The solutions are -1/3 and 0, as above.

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3 years ago

Give two of your own examples of square roots that are irrational numbers and two rational numbers .

Vikentia [17]

Irrational

$\sqrt{2}$

$\sqrt{3}$

Rational:

$\sqrt{1}$

$\sqrt{4}$

6 0

3 years ago

Read 2 more answers

Solve the following quadratics. State the FACTORS AND SOLUTIONS. 1. 2x^2 - 7x + 3 2. 3x^2 + 7x +2

tekilochka [14]

Answer:

1. x = 3, 1/2 (solutions); (x - 3)(2x - 1) (factors)

2. x = -1/3, -2 (solutions); (3x + 1)(x + 2) (factors)

Step-by-step explanation:

1. 2x^2 - 7x + 3

To solve problem 1, you will need to identify your a, b, and c values in this quadratic function.

Since this problem is in standard form, it will be easy to identify these values. The standard form of a quadratic function is ax^2 + bx + c.

The a value is 2, the b value is -7, and the c value is 3 if we use our standard form and see which numbers are plugged into it.

Since we know that

a = 2
b = -7
c = 3

we can use the quadratic formula: $x = \frac{-b~\pm~\sqrt{b^2~-~4ac} }{2a}$

Substitute the a, b, and c values into the quadratic formula: $x=\frac{-(-7)\pm\sqrt{(-7)^2-4(2)(3)} }{2(2)}$

Now simplify using the laws of pemdas: $x=\frac{7\pm\sqrt{(49)-(24)} }{4}$

Simplify even further: $x=\frac{7\pm\sqrt{(25)} }{4} \rightarrow x=\frac{7\pm (5) }{4}$

Now split this equation into two equations to solve for x: $x=\frac{12 }{4} ~~and~~ x=\frac{2 }{4}$

12/4 can be simplified to 3, and 2/4 can be simplified to 1/2.

This means your solutions to problem 1 is 3, 1/2.

$\boxed {x=3,\frac{1}{2} }$

There is also another way to solve for the quadratic functions, and this was by factoring.

If you factor 2x^2 - 7x + 3 using the bottoms-up method, you will get (x - 3)(2x - 1).

After factoring, solving for the solutions is simple because all you have to do is set each factor to 0.

x - 3 = 0
2x - 1 = 0

After solving for x by adding 3 to both sides, or by adding 1 to both sides then dividing by 2, you will end up with the same solutions: x = 3 and x = 1/2.

2. 3x^2 + 7x + 2

To save time I'll be using the bottoms-up factoring method, but remember to refer back to problem 1 (quadratic formula) if you prefer that method.

Factor this quadratic function using the bottoms-up method. After factoring you will have (3x + 1)(x + 2). These are your factors.

Now to solve for x and find the solutions of the quadratic function, you will set both factors equal to 0.

3x + 1 = 0
x + 2 = 0

Solve.

First factor: 3x + 1 = 0

Subtract 1 from both sides.

3x = -1

Divide both sides by 3.

x = -1/3

Second factor: x + 2 = 0

Subtract 2 from both sides.

x = -2

Your solutions are x = -1/3 and x = -2.

$\boxed {x = -\frac{1}{3} , -2}$

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3 years ago

Matteo was told he could spend AT MOST $80 to spend at the mall. He bought lunch for $25. He wants to buy phone cases for his fr

NeX [460]

80 - 25 = 55. 55 divided by 5 = 11 phone cases.

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3 years ago

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kvasek [131]

Answer:

5.89 mi/h

Step-by-step explanation:

This problem can be solved by using different methods. I will use vectors since it's the simplest way in which we can solve it. This can be solved by using related rates of change though.

First, we start by drawing a diagram with the velocity vectors.

A= velocity of the first person

B= velocity of the second person

C= velocity in which they are moving away from each other.

Since there is no acceleration in the problem, we can suppose we are talking about constant speeds, so the velocity at which they are moving away from each other will always remain constant. (It doesn't matter what time it is, the velocity will always be the same)

Having said this we can solve this problem by using the components, by using law of cosines or graphically. I will use law of cosines. The idea is to find the length of side c.

Law of cosines:

$C^{2}=A^{2}+B^{2}-2ABcos \gamma$