HELP ME PLEASE ASAP ASAP
1 answer:
You might be interested in
Answer:
Quadrant III
Step-by-step explanation:
The attached picture shows graph of 4 such linear functions with the conditions given in the problem. ALL of them DO NOT pass through Quadrant III.
The graphs shown are of the functions:
<em>So, any linear function of the form with
and
does not pass through Quadrant III. Answer choice 3 is correct.</em>
Answer:
x ≥ -1/2
Step-by-step explanation:
We know that we cannot graph imaginary numbers. Therefore, our <em>x </em>value has to be greater than or equal to 0:
To find our domain, we need to set the square root equal to zero:
√(4x + 2) = 0
4x + 2 = 0
4x = -2
x = -1/2
We now know that no value below -1/2 can be used or we will get an imaginary number. Therefore, our answer is x ≥ -1/2
Alternatively, we can graph the function and analyze domain:
