The answer is 120 sections.
Here's an explanation:
The rope is 105 feet long, and each section needs to be 7/8 feet. So to find the number of sections, you need to divide 105 by 7/8. 105 divided by 7/8 gives you the quotient 120. So there are 120 sections.
Answer:
a or the first one
Step-by-step explanation:
built:Different
Answer:
4.4% of the population with IQ between 120 and 125.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 100
Standard Deviation, σ = 15
We are given that the distribution of IQ scores is a bell shaped distribution that is a normal distribution.
a) Let X be a person's IQ score.
Then, density functions for IQ scores is given by:

b) P(population with IQ between 120 and 125.)
Formula:



Answer
Find out the value of x.
To prove
Definition of mid- segment
It is a segment connecting the midpoints of two sides of a triangle.
It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
As shown in the triangle given below.
As given
DE = 5x and BC = 11x – 15
Thus




15 = 11x - 10x
15 = x
Therefore the value of x is 15 .
Let x represent the height of the model.
We have been given that a construction company built a scale model of a building. The model was built using a scale of 3 inches = 32 feet. We are asked to find the height of the model, if the building is expected to be 200 feet tall.
We will use proportions to solve our given problem as:

Upon substituting our given values, we will get:




Therefore, the model will be 18.75 inches tall.