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ElenaW [278]
3 years ago
5

How many, and what type of solutions, does 6x squared - 2x + 7 = 0 have

Mathematics
1 answer:
harkovskaia [24]3 years ago
5 0

Answer:

the correct answer is 2 no real solurions hope this helps

You might be interested in
2^x + 3^y = 9<br>2^x+1 - 3^y+1=8<br>find x and y​
Taya2010 [7]

Suppose :

2^x = t ..**&**.. 3^y = u

_____________________________

t + u = 9 × 3 3t + 3u = 27

=====》

2t - 3u = 8 2t - 3u = 8

+ __________

5t = 35

5 × t = 5 × 7

t = 7

&

u = 2

________________________________

Thus :

2^x = 7 ===》 x = Log _ 2 { 7 }

3^y = 2 ===》 y = Log _ 3 { 2 }

8 0
3 years ago
John runs 4 miles in 30 minutes. at the same rate, how many miles would he run in 48 minutes?
dimulka [17.4K]
Make a ratio, then cross multiply.

4/30=x/48

30x=4x48
30x=192
x=6.4
3 0
3 years ago
Which expression is equivalent to √48x5, if x&gt; 0?
Lerok [7]

Answer:

C. 4x²√(3x)

Step-by-step explanation:

if x > 0

\sqrt{48x^{5}} =\sqrt{48} \times \sqrt{x^{5}}

          =\sqrt{16\times 3} \times \sqrt{x^{4}\times x}

          =\sqrt{16} \times \sqrt{3} \times \sqrt{x^{4}} \times \sqrt{x}

          =4\times \sqrt{3} \times \sqrt{\left( x^{2}\right)^{2}  } \times \sqrt{x}

          =4\times \sqrt{3} \times x^{2}\times \sqrt{x}

          =4\times x^{2} \times  \sqrt{3} \times \sqrt{x}

          =4\times x^{2}\times \sqrt{3x}

8 0
1 year ago
RESPOND QUICK
mrs_skeptik [129]

Answer:

A

Step-by-step explanation:

3/24=9/72        3*3=9    24*3=72      x=3

3/9=y/12         9/3=3        12/3=4      y=4

X=3 y=4

6 0
3 years ago
Triangles P Q R and S T U are shown. Angles P R Q and T S U are right angles. The length of P Q is 20, the length of Q R is 16,
dimaraw [331]

Answer:

\angle P

Step-by-step explanation:

Given

\triangle PRQ = \triangle TSU = 90^o

PQ = 20     QR = 16    PR = 12

ST = 30       TU = 34    SU = 16

<em>See attachment</em>

Required

Which sine of angle is equivalent to \frac{4}{5}

Considering \triangle PQR

We have:

\sin(P) = \frac{QR}{PQ} --- i.e. opposite/hypotenuse

So, we have:

\sin(P) = \frac{16}{20}

Divide by 4

\sin(P) = \frac{4}{5}

Hence:

\angle P is correct

7 0
3 years ago
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