Step-by-step explanation:
(x^4)^3=(x^3)^4 , true
=> x^(4×3) = x^(3×4) = x^12
13^4 x 13^7= (13^4)^7, false
13^(4+7) = 13^11
(13^4)^7 = 13^(4×7) = 13^28
y^5 x y^0/y^3=(y^2)^1 , true
y^5 x y^0/y^3 = y^(5+0-3) = y^2
(y^2)^1 = y^(2×1) = y^2
q^0 x q^5/q^2=(q^3)^2/q^3, true
q^0 x q^5/q^2= q^(0+5-2)= q^3
(q^3)^2/q^3 = q^(3×2-3) = q^3
Answer:
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Answer:
the answer is on photomath
Answer:
Step-by-step explanation:
In a quadratic equation in the Standard form
You need to remember that "a", "b" and "c" are the numerical coefficients (Where "a" is the leading coefficient and it cannot be zero: ).
You can observe that the given quadratic equation is written in the Standard form mentioned before. This is:
Therefore, you can identify that the values of "a", "b" and "c" are the following:
Answer:
99
Step-by-step explanation:
U will do the one outside first
122+1-4(6)
=123-24
= 99