Answer:
1, 1.5, -1 1/5
Step-by-step explanation:
96.47 would be your answer rounded to the nearest hundredth
400 because I said so and u are asking me is here is the answer
Okay, so, to find out if an equation has one solution, an infinite number of solutions, or no solutions, we must first solve the equation:
(a) 6x + 4x - 6 = 24 + 9x
First, combine the like-terms on both sides of the equal sign:
10x - 6 = 24 + 9x
Now, we need to get the numbers with the variable 'x,' on the same side, by subtracting, in this case:
10x - 6 = 24 + 9x
-9x. -9x
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X - 6 = 24
Now, we do the opposite of subtraction, and add 6 to both sides:
X - 6 = 24
+6 +6
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X = 30
So, this particular equation has one solution.
(a). One solution
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(b) 25 - 4x = 15 - 3x + 10 - x
Okay, so again, we combine the like-terms, on the same side of the equal sign:
25 - 4x = 25 - 2x
Now, we get the 2 numbers with the variable 'x,' to the same side of the equal sign:
25 - 4x = 25 - 2x
+ 2x + 2x
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25 - 2x = 25
Next, we do the opposite of addition, and, subtract 25 on each side:
25 - 2x = 25
-25 -25
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-2x = 0
Finally, because we can't divide 0 by -2, this tells us that this has an infinite number of solutions.
(b) An infinite number of solutions.
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(c) 4x + 8 = 2x + 7 + 2x - 20
Again, we combine the like-terms, on the same side as the equal sign:
4x + 8 = 4x - 13
Now, we get the 'x' variables on the same side, again, and, we do that by doing the opposite of addition, which, is subtraction:
4x + 8 = 4x - 13
-4x -4x
______________
8 = -13
Finally, because there is no longer an 'x' or variable, we know that this equation has no solution.
(c) No Solution
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I hope this helps!
Answer:
sorry that hard a only in 5th grade
