D=vt+(v+12)t
d=vt+vt+12t
d=2vt+12t
d=2t(v+6), and we are told that d=232 and t=2
2(2)(v+6)=232
4(v+6)=232
v+6=58
v=52
So the slower car is travelling at 52 mph and the faster car is traveling at 64 mph.
Answer:
01001000 01100001 01101000 01100001 01101000 01100001 00100000 01111001 01101111 01110101 00100000 01101010 01110101 01110011 01110100 00100000 01100111 01101111 01110100 00100000 01110011 01100011 01100001 01101101 01101101 01100101 01100100 00100000 01100010 01111001 00100000 01101101 01100101 00100000 01001001 01101101 00100000 01110100 01101111 00100000 01100101 01110000 01101001 01101011 00100000 00111011 00101001 00100000 01101000 01100001 01101000 01100001 01101000 01100001 01101000 01100001 01101000 01100001 01101000 01100001 01101000 01100001 01101000 01100001 01101000 01100001 01101000 01100001 01101000 01100001 01101000 01100001 01101000 00100000 01001001 00100000 01001100 01001001 01001011 01000101 00100000 01011001 01000001 01000011 01010101 01010100 00100000 01000111 00100000 00101010 01010011 01001100 01000001 01010000 00100000 01000001 01001000 01001000 01001000 01001000 01001000 01001000 01001000 01001000 01001000 01001000 01001000 01001000 01001000 01001000 01001000 01001000 01001000 01001000 01001000 01001000 01001000
Step-by-step explanation:
Answer:
hold up lemma check
Step-by-step explanation:
To find the max area you would use length times width times height
Answer:
1800
Step-by-step explanation:
→ First of all we need to find the prime factorisation of the numbers.
18 = 2 × 3 × 3 or 2 × 3²
40 = 2 × 2 × 2 × 5 or 2³ × 5
75 = 3 × 5 × 5 or 5² × 3
→ Now find the number that appear twice or more and write them down
3 and 3 from 18
2, 2 and 2 from 40
5 and 5 from 75
→ Now multiply all of these numbers together
3 × 3 × 2 × 2 × 2 × 5 × 5 = 3² × 2³ × 5² = 1800