Solve 7x/3< 2. please

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

6 0

Answer:

x < 6/7

Step-by-step explanation:

Multiply both sides by 3 to get 7x < 6

Divide by 7

x < 6/7

You might be interested in

Hello I need help<br> Find the missing side lengths, leave your answers as radicals in simplest form

Jet001 [13]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

$y = \frac{1}{2} \times \frac{8 \sqrt{3} }{3} \\$

$y = \frac{4 \sqrt{3} }{3} \\$

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

$x = \frac{ \sqrt{3} }{2} \times \frac{8 \sqrt{3} }{3} \\$

$x = \frac{8 \times { \sqrt{3} }^{2} }{2 \times 3} \\$

$x = \frac{8 \times 3}{2 \times 3} \\$

$x = \frac{8}{2} \\$

$x = 4$

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

4 0

2 years ago

Are the numbers (2,3)(1,5)(2,7) a function ?

Arturiano [62]

Firstly they are not numbers, they are ordered pairs or points with a form $(x,f(x))$ yes they probably lie on a function graph but that would be rather impossible to find out. The function may be linear, exponential, logarithmic etc. we can't tell. All we can tell is that if these ordered pairs $P_{1,2,3}$ lie on a function graph $P_{1,2,3}\in G_f$ where $G_f=\{(x,f(x)):\forall x\in D_f\wedge f(x)\in T_f\}$ where D is definition set of function defined x's and T a transformation set of f(x)'s for this function. So yes they may lie on some lambda function but they themselves are nothing but an ordered pairs with no meaningful connection.