Answer:
B
Explanation:
Great variations in temperature and pH from the optimum that an enzyme needs can affect its function. pH affects ionization of the functional groups of amino acids. The interaction of charges of these amino groups helps in stabilizing loops such as those of beta sheets and alpha helices and give the protein its an appropriate shape to function.
Temperatures, on the other hand, while it does not change the ionization of the functional side groups of amino acids, it breaks these bonds of the interactions by giving the molecules enough energy to break free from these bonds hence denaturing the protein.
Answer:
Explanation:
The observed frequency of the double crossovers (DCOs) is 20/1000, or 0.02. If there is no interference then this will be the same as the expected, which is just the product of the single crossover frequencies, that is, SCO frequency (a-b) x SCO freq. (b-c) = 0.02.
(a) Any combination of map distances whose product (a-b) x (b-c) = 0.02 is possible. However, three are most likely:
a 20 mu b 10 mu c
a 10 mu b 20 mu c
a 14.14 mu b 14.14 mu c
(b) The distances would be exactly the same.
(c) The expected number of DCO progeny would be 17.
Answer:
Statement C is the only one that is necessarily true for exons 2 and 3. It is also true for exons 7 and 8. While statements A and B could be true, they don’thave to be. Because the protein sequence is the same in segments of the mRNA that correspond to exons 1 and 10, neither choice of alternative exons (2 versus 3, or 7 versus 8) can alter the reading frame. To maintain the normal reading frame—whatever that is—the alternative exons must have a number of nucleotides that when divided by 3 (the number of nucleotides in a codon) give the same remainder. Since the sequence of the a-tropomyosin gene is known, it is possible to check to see the actual state of affairs. Exons 2 and 3 both contain the same number of nucleotides, 126, which is divisible by 3 with no remainder.
Answer:
The answer to your question is: letter C
Explanation:
From the graph, we can conclude that catalase has a low activity at low temperatures. Activity increases a little at 30°C and this process is the highest at 40°C, after this temperature, activity disminishes again.
Options:
A. This option is wrong because the number of bubbles at this temperatures is low, maybe the enzyme is already denatured.
B. This answer is wrong, at 30°C the enzyme shows a low activity.
C. This answer is correct because at this temperature the enzyme produces the higher amount of bubbles.
D. The activity of the enzyme at 0°C was not tested.
Switch A and D, but other than that your answers are correct.
An astronomical body is an object in space.
A comet is a celestial object consisting of a nucleus of ice and a stream of gas and dust.
A moon is an astronomical body that orbits around a planet.
A galaxy is a system of start held by gravitational attraction.
