Answer:
The club must sell 18 jackets to break even
Step-by-step explanation:
Given:
C = 20x + 270
Where,
x = number of jackets
Equation for revenue R in terms of the number of jackets
Revenue = price × quantity
Price of the jacket = $35
Quantity of the jacket = x
Revenue = price × quantity
= 35 * x
R = 35x
Break even point is the point at which cost is equal to revenue, that is, no gain; no loss.
Cost = revenue
20x + 270 = 35x
270 = 35x - 20x
270 = 15x
x = 270 / 15
= 18
x = 18 jackets
The club must sell 18 jackets to break even
Answer:
18.5
Step-by-step explanation:
You have to divide. If you leave it as a fraction, you won't be able to simplify. You can check my answer by multiplying 18.5 * 2
<u>Answer:4.75</u>
<u>Since we don't have a total cost we will write an equation that will allow us to find the cost of x. The equation is 4x= 2x + $3 + $3.75 + $2.75. Now that we have our equation we are going to start by adding 3, 3.75, and 2.75. When added together, they come out with a total of 9.5. Now the equation becomes 4x= 2x + $9.50. Since we have our new equation we are going to subtract 2x from both sides of the equation. We now have the equation 2x= $9.50. Finally, you will divide both sides by 2. This leaves us with the final outcome x= $4.75. This means that one glues stick cost $4.75. Let's check by substituting $4.75 as the value of x in the expressions 4x is Carlo's total and 2x + $3 + $3.75 + $2.75 is Helen's total. First we do 4x, 4 multiplied by 4.75 equals 19, so Carlo spent $19 on art supplies. Now we do 2x + $3 + $3.75 + $2.75, which is 9.5 added to 9.5 and equals 19. So Helen spent $19 on art supplies. This proves that the cost of one glue stick, x, is equal $4.75.</u>
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I think Deal B correct me if im wrong..
Answer:
36*sqrt(3)
Step-by-step explanation:
Remark
Use the Pythagorean theory to find the height. Use that height to find the area of the rectangle and the triangle Or
You can find the area of the trapezoid which requires only 1 step after you find the height.
Height
c = 8
b = 4
a = ?
a^2 + b^2 = c^2
a^2 + 4^2 = 8^2
a^2 + 16 = 64
a^2 = 64 - 16
a^2 = 48
a^2 = 16 * 3
sqrt(a^2) = sqrt(16*3)
a = 4 * sqrt(3)
That's the height
Trapezoid
b1 = 7
b2 = 7 + 4 = 11
h = 4*sqrt(3)
Area = (b1 + b2)*h / 2
Area = (7 + 11)* 4*sqrt(3)/2
Area = 18 * 2 sqrt(3)
Area = 36* sqrt(3)