At a benefit concert, eleven bands have volunteered to perform but there is only enough time for eight of the bands to play. Ho
1 answer:
Answer:
The correct answer is
Step-by-step explanation:
At a benefit concert, eleven bands have volunteered to perform.
There is only enough time for eight of the bands to play.
We need to find how many lineups are possible.
We would need to choose 8 bands out of 11 and their arrangements should be unique. Also that no band can perform twice.
There fore the number of possible line ups are = 165 ways.
Therefore 8 bands out of the 11 can lineup in 165 different ways and perform at the benefit concert.
You might be interested in
Let z = sin(x). This means z^2 = (sin(x))^2 = sin^2(x). This allows us to go from the equation you're given to this equation: 7z^2 - 14z + 2 = -5
That turns into 7z^2 - 14z + 7 = 0 after adding 5 to both sides. Use the quadratic formula to solve for z. The only solution is z = 1 (see attached image). Since we made z = sin(x), this means sin(x) = 1. All solutions to this equation will be in the form x = (pi/2) + 2pi*n, which is the radian form of the solution set. If you need the degree form, then it would be x = 90 + 360*n
The 2pi*n (or 360*n) part ensures we get every angle coterminal to pi/2 radians (90 degrees), which captures the entire solution set.
Note: The variable n can be any integer.
