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Minchanka [31]
3 years ago
6

10000-10000+100000-100000

Mathematics
2 answers:
Semenov [28]3 years ago
7 0

10000 - 10000 = 0

0 + 100000 = 100000

100000 - 100000 = 0

Your answer is 0 then?

lbvjy [14]3 years ago
5 0

Answer:

0

Step-by-step explanation:

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Llana [10]

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4 0
3 years ago
HELO I NEED HELP ASAP
jonny [76]

Answer:

C. The amount Kayla charges per children

Step-by-step explanation:

Y=mx+b

m=Slope

x=Number of children

m=2 means 2 dollars per x(children)

6 0
2 years ago
Use Synthetic Division to divide 6x^3-10x^2+20 by x+1<br><br> Quotient:_____<br><br> Remainder:_____
exis [7]

Answer:

the quotient is 6x^2 - 16x + 16, and the remainder is just 4

Step-by-step explanation:

The polynomial 6x^3-10x^2+20 has coefficients {6, -10, 0, 20}.  Division by the binomial x + 1 requires that we use -1 as the divisor.  The synthetic division setup becomes:

-1   /    6    -10    0    20

                 -6    16   -16

     -----------------------------

          6     -16   16       4

Taking the coefficients {6, -16, 16}, we write the quotient as

6x^2 - 16x + 16, and the remainder as just 4.

6 0
3 years ago
Perform the indicated operation 2 3/8 x 5 3/4
Butoxors [25]
Hello!

Change each mixed number to an improper fraction to make it easier

2 3/8 = 19/8

5 3/4 = 23/4

Now, multiply

19/8  × 23/4 = 437/32 = 13 21/32

Answer ⇒ 13 21/32

4 0
3 years ago
Read 2 more answers
Suppose that you have eight cards. Five are green and three are yellow. The five green cards are numbered 1, 2, 3, 4, and 5. The
Marina86 [1]

Answer:

Step-by-step explanation:

Given that you have eight cards. Five are green and three are yellow. The five green cards are numbered 1, 2, 3, 4, and 5. The three yellow cards are numbered 1, 2, and 3. The cards are well shuffled. You randomly draw one card.

G = card drawn is green

Y = card drawn is yellow

E = card drawn is even-numbered

List:

Sample space = {G1, G2, G3, G4, G5, Y1, Y2, Y3}

2) P(G) = 5/8

3) P(G/E) = P(GE)/P(E)

GE = {G2, G4}

Hence P(G/E) = 2/5

4) GE = {G2, G4}

P(GE) = 2/8 = 1/4

5) P(G or E) = P(G)+P(E)-P(GE)

= 5/8 + 3/8-2/8 = 3/5

6) No there is common element as G2 and G4

Cannot be mutually exclusive

6 0
3 years ago
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