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Blizzard [7]
4 years ago
6

Find the angle between the given vectors to the nearest tenth of a degree. u = <2, -4>, v = <3, -8>

Mathematics
1 answer:
NikAS [45]4 years ago
8 0

You can use

cos(theta) = u · v / ║u║║v║

that will come out to:

u = 2 x (-4) = -8

v = 3 x (-8) = - 24

u · v = -16

║u║ = \sqrt{(2)^{2} + (-4)^{2}  }  = \sqrt{20} = 2\sqrt{5}

║v║ = \sqrt{(3)^{2} + (-8)^{2}  } = \sqrt{73}

cos(theta)  = -16/2 \sqrt{365}

and to find (theta), you can now do

theta = (cos^-1) ( -16/2 \sqrt{365})

I don't have a calculator, but you can solve that final problem to find theta

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