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tigry1 [53]
2 years ago
6

PLEASE help with these math questions

Mathematics
1 answer:
SIZIF [17.4K]2 years ago
7 0
Questions 1, 2, 3, and 4 are exercises to give you practice with
common denominators.  For each of these questions, change all
the fractions to common denominators, and the answers jump out at you.

#1).  5/12 = 25/60
         2/5  =  24/60
Make um negative, and then you'll have the answer right away.


#2).  The one that's negative is obviously the least.
Both positive ones must be bigger than the negative one.
For the positive ones:

           2/5  =  6/15
           2/3  =  10/15 .
Now it's easy.


#3).  This is tough.  The least common denominator is  2,520 !
It's probably easier to just do the divisions and get the decimals
for each fraction.

               -5/8  =  -0.625
               -7/9  =  -0.777...
               -4/5  =  -0.8
               -3/7  =  -0.428...
Now it's easy to line um up.


#4).  Sneaky one.
      Look closely at each fraction.
      B, C, and D are all less than 1, so they're not between 1 and anything more than 1.
      8/5 is the only one that's more than 1.     


#5).  A fraction is just a short way to write a division problem.
When you see a fraction, it means

               "the top number divided by the bottom number" .

When you actually do the division, the quotient you get
is the decimal form of the fraction.

To change a decimal into a percent,
move the decimal point two places that way  ==> .

The numbers in the boxes at the bottom of #5 are the correct numbers,
but they both should be negative.  (because the -3/8 is negative)
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PLEASE SOLVE AND CHECK. SHOW COMPLETE SOLUTION
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<u>Solution</u><u>:</u>

\sqrt{4x + 13}  = x + 2

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=  > ( \sqrt{4x + 13} ) ^{2}  = (x + 2) ^{2}

  • Now, square root and square gets cancel out in the LHS. And in the RHS, apply the identity: (a + b)² = a² + 2ab + b².

=  > 4x + 13 =  {(x)}^{2}  + 2 \times x \times 2 + (2) ^{2} \\  =  > 4x + 13 =  {x}^{2}   + 4x + 4

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=  > 4x - 4x + 13 - 4 =  {x}^{2}  \\

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=  >  {x}^{2}  = 9 \\  =  >  x =  \sqrt{9}  \\  =  > x = ±3

<u>Answer</u><u>:</u>

<u>x </u><u>=</u><u> </u><u>±</u><u> </u><u>3</u>

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