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Nesterboy [21]
3 years ago
5

How do you find the quotient of positive and negative decimals?

Mathematics
2 answers:
aivan3 [116]3 years ago
6 0

Answer:

When you divide a negative number by a positive number then the quotient is negative. When you divide a positive number by a negative number then the quotient is also negative.

Step-by-step explanation:

AfilCa [17]3 years ago
4 0

Answer:

I am explain you in image

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The graph below is a function.<br><br> True or false?
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Answer:

true!

Step-by-step explanation:

hi, this graph is a function because it passes the vertical line test. there are no x-values with 2 y-values for the same x.

3 0
3 years ago
9+10=?<br> A. 21<br> B. 4<br> C. 19<br> D. 18
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A plumbers plastic pipe is 4 m long, has an inside diameter of 4.0 cm and an outside diameter of 5.0cm. What is the volume of th
SCORPION-xisa [38]

Answer: V=0.0028278\ m^3

Step-by-step explanation:

Given

Length of the pipe l=4\ m

Inside diameter of the pipe d_i=4\ cm

Outside diameter of the pipe d_o=5\ cm

Volume of the pipe

\Rightarrow V=\dfrac{\pi }{4}[d_o^2-d_i^2]\\\\\text{Insert the values}\\\\\Rightarrow V=\dfrac{\pi}{4}[5^2-4^2]\times 10^{-4}\times 4\\\\\Rightarrow V=28.278\times 10^{-4}\ m^3\\\\\Rightarrow V=0.0028278\ m^3

5 0
3 years ago
The sum of two numbers is 43 . The smaller number is 19 less than the larger number. What are the numbers?
Setler [38]
Let the smaller number be x and the larger number be y.
We can calculate this by using simultaneous equation, aka listing 2 equations out.
From given,
X + y = 43
Let this be equation no. 1
X + 19 = y
Let this number be equation 2.
We can do simultaneous equations either by substitute method or elimination. In this case I'm using substitute.
We can already obtain the value of y (in terms of x) in euqation no. 2, so all we gonna do is to put y into equation 1.
X + x + 19 = 43
Solve this by algebra.
2x = 43 - 19
X = 12
Now we know the exact value of x
Now substitute x = 12 into equation no. 2
12 + 19 = y
Y = 31
So the answer is 12 and 31
7 0
2 years ago
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