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Naya [18.7K]
3 years ago
13

Solve x+1>10, x+11>20, and x+21>30

Mathematics
2 answers:
barxatty [35]3 years ago
7 0
X+1>10
x>10-1
x>9

x+11>20
x>20-11
x>9

x+21>30
x>30-21
x>9

\framebox[1.1\width]{Godspeed!} \par

Nesterboy [21]3 years ago
5 0
a)  \\  x+1>10 \\ x>10-1  \\ x>9 \\  \\  \\ b) \\  x+11>20 \\ x>20-11 \\ x>9 \\  \\ \\  c) \\ x+21>30 \\ x>30-21 \\ x>9 \\  \\  \\ \framebox[1.1\width]{Good Luck !} \par
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(3) Which of the fractions does not belong to the group ? 2/3 , 4/7 ,9/2,1/6​
Gnesinka [82]

Answer:

9/2

Step-by-step explanation:

9/2 is an improper fraction, as the numerator is greater than the denominator

4 0
4 years ago
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Evaluate \dfrac n6+2
vagabundo [1.1K]
<h2>Explanation:</h2><h2></h2>

Here we have the following expression:

\frac{n}{6}+2 \\ \\ \\ When: \\ \\ n=12

What we need to do is to substitute n=12 into our expression. Therefore:

\frac{n}{6}+2 \\ \\ \frac{n}{6}+2 =\frac{12}{6}+2 =2+2=4

Finally, when evaluating n=12 into the expression the result is 4.

8 0
3 years ago
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What is the range of y equals log 8 x
azamat

Answer:

  (-∞, ∞)

Step-by-step explanation:

The range of any log function is <em>all real numbers</em>.

4 0
3 years ago
A cyclist rides 225 m each minute.About how long does it take to ride 15km? Show all fo your work
Elan Coil [88]
Speed = 225 metres per minute

Distance = 15 km = 15,000 metres

---------------------------------------------------

s=d/t

ts=d

Therefore: t=d/s

--------------------------------------------------

Time = Distance / Speed

Time = (15,000 metres) / (225 metres per minute)

--------------------------------------------------

Let's work it out:

Time=\frac { 15,000\quad metres }{ \frac { 225\quad metres }{ 1\quad minute\left( s \right)  }  } \\ \\ =\frac { 15,000\quad metres }{ 1 } \cdot \frac { 1\quad minute\left( s \right)  }{ 225\quad metres } \\ \\ =\frac { 15,000 }{ 225 } minutes

\\ \\ =\frac { 200 }{ 3 } minutes\\ \\ \frac { 200 }{ 3 } minutes\quad =\quad 66\quad minutes,\quad 40\quad seconds
6 0
4 years ago
Find the least common denominator for these two rational expressions. B/b^2 -64 -7b/b^2+7b-8
san4es73 [151]

Answer:

The least common denominator is (b-8)(b+8)(b-1)

Step-by-step explanation:

We are given expression as

\frac{b}{b^2-64}-\frac{7b}{b^2+7b-8}

Firstly, we will factor both denominators

b^2-64=b^2-8^2=(b-8)(b+8)

b^2+7b-8=(b+8)(b-1)

so, we can plug it back

\frac{b}{(b-8)(b+8)}-\frac{7b}{(b+8)(b-1)}

First term denominator is

(b-8)(b+8)

Second term denominator is

(b+8)(b-1)

So,

Least common denominator will be

(b-8)(b+8)(b-1)

So, we get

LCD=(x-8)(x+8)(x-1)


3 0
3 years ago
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