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ra1l [238]
3 years ago
13

Which type of electromagnetic radiation has a longer wavelength than visible light?

Chemistry
2 answers:
Musya8 [376]3 years ago
7 0

Answer:

Explanation:

The wavelenght of a electromagnetic radiation is related with it's energy.

The longer the wavelenght the lower the energy.

The ekectromagnetic radiation that have an energy larger than the visible light is Gamma Rays, x-rays and ultraviolet radition, so it have a shorter wavelenght.

And the Infrared Radiation has an energy smaller than the visible light, having a longer wavelenght.

Feliz [49]3 years ago
5 0
Infrared radiation if i’m correct
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What molarity is made when 36.5 g HCl is mixed into 250 mL of solution?​
Dominik [7]

Answer:

The molarity of the HCl solution is 4M.

Explanation:

Molarity=\frac{number\:of\:moles}{Volume\:of\:solution\:in\:L}\\ \\The\:volume\:of\:solution=250mL=0.25L\\\\Number\:of\:moles=\frac{weight\:of\:HCl\:in\:solution}{molecular\:weight\:of\:HCl}\\ \\Molecular\:weight\:of\:HCl=36.5g\\\\The\:weight\:of\:HCl\:in\:solution=36.5g\\\\Number\:of\:moles\:of\:HCl=\frac{36.5}{36.5}=1\:mole\\\\The\:molarity\:of\:HCl\:solution=\frac{1}{0.25}=4M

Hence, the molarity of the HCl solution = 4 M

5 0
3 years ago
How many atoms are found in the chemical formula below
Stolb23 [73]

Answer:

2 atoms

Explanation:

There are 2 atoms in element NaCl. This is because there is 1 atom of Na (sodium) and 1 atom of Cl (chlorine) in each NaCl molecule. Elements by themselves do not have a "number of atoms"- if you're talking about the atomic number, it's the number of protons (or electrons in a neutral atom) of an element.

6 0
3 years ago
Read 2 more answers
The picture below shows a warm air mass caught between two cooler air masses. What is this type of front called? Plz, I really n
pentagon [3]

An occluded front forms when a warm air mass is caught between two cooler air masses.

6 0
3 years ago
SynthesizeWrite the instructions you would give a classmate to locate the point 27°18'N, 19°2'E on a globe.
SVEN [57.7K]

Answer:

<em>It is known by almost everyone Earth is divided into longitudes and latitudes which are imaginary lines that cut Earth into 2 equal parts.</em>

Explanation:

The main use of dividing Earth into so many imaginary lines is to know no of places perfect location in numbers.  Direction and  tell tales can make the place talked about a bit confusing but the exact longitudes and latitudes known pill and someone in exact  position.

So in the positions given the question  27 ° and 19 ° show the distance of longitude from Prime Meridian While 18 ° and two degrees show the distance from the equator.

6 0
3 years ago
What we call "tin cans" are really iron cans coated with a thin layer of tin. The anode is a bar of tin and the cathode is the i
UNO [17]

Answer:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

Explanation:

Although the context is not clear, let's look at the oxidation and reduction processes that will take place in a Fe/Sn system.

The problem states that anode is a bar of thin. Anode is where the process of oxidation takes place. According to the abbreviation 'OILRIG', oxidation is loss, reduction is gain. Since oxidation occurs at anode, this is where loss of electrons takes place. That said, tin loses electrons to become tin cation:

Sn (s)\rightarrow Sn^{2+} (aq) + 2e^-

Similarly, iron is cathode. Cathode is where reduction takes place. Reduction is gain of electrons, this means iron cations gain electrons and produce iron metal:

Fe^{2+} (aq) + 2e^-\rightarrow Fe (s)

The net equation is then:

Sn (s) + Fe^{2+} (aq)\rightarrow Fe (s) + Sn^{2+} (aq)

However, this is not the case, as this is not a spontaneous reaction, as iron metal is more reactive than tin metal, and this is how the coating takes place. This implies that actually anode is iron and cathode is tin:

Actual anode half-equation:

Fe (s)\rightarrow Fe^{2+} (aq) + 2e^-

Actual cathode half-equation:

Sn^{2+} (aq) + 2e^-\rightarrow Sn (s)

Actual net reaction:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

6 0
3 years ago
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