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REY [17]
3 years ago
11

How do i simplify simplify 3x + 5 - 2x - 2 ?

Mathematics
2 answers:
GenaCL600 [577]3 years ago
7 0

Answer:

x + 3

Step-by-step explanation:

Combine like terms.

You can subtract the 2x from the 3x and the 2 from the 5.

Marina CMI [18]3 years ago
4 0
Combine like terms:
3x+(-2x)= x
5+(-2)= 3
* the subtraction sign cancels the addition sign bc they are opposite operations, therefore you subtract.

add your results and you get: x+3
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Find the volume of a cone with the radius of 14, and a height of 9. (Hint:
erastova [34]

Answer:

The answer is 1846.32 units³.

Step-by-step explanation:

Given that the base of a cone is a circle so the area of circle is A = πr². You have to substitute the following values into the formula :

v =  \frac{1}{3}  \times \pi \times  {r}^{2}  \times h

Let π = 3.14,

Let r = 14,

Let h = 9,

v =  \frac{1}{3}  \times 3.14 \times  {14}^{2}  \times 9

v = 1846.32 \:  {units}^{3}

4 0
4 years ago
A statistics instructor who teaches a lecture section of 160 students wants to determine whether students have more difficulty w
bulgar [2K]

Answer:

The null and alternative hypothesis are:

H_0: \mu_X-\mu_Y=0\\\\H_a:\mu_X-\mu_Y> 0

P-value=0.1996

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean score μX on one-tailed hypothesis test questions is higher than the mean score μY on two-tailed hypothesis test questions .

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that the mean score μX on one-tailed hypothesis test questions is higher than the mean score μY on two-tailed hypothesis test questions .

Then, the null and alternative hypothesis are:

H_0: \mu_X-\mu_Y=0\\\\H_a:\mu_X-\mu_Y> 0

The significance level is 0.05.

The sample X (one-tailed), of size nX=80 has a mean of 7.8 and a standard deviation of 1.06.

The sample Y (two-tailed), of size nY=80 has a mean of 7.64 and a standard deviation of 1.32.

The difference between sample means is Md=0.16.

M_d=M_X-M_Y=7.8-7.64=0.16

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_X^2+\sigma_Y^2}{n}}=\sqrt{\dfrac{1.06^2+1.32^2}{80}}\\\\\\s_{M_d}=\sqrt{\dfrac{2.866}{80}}=\sqrt{0.036}=0.189

Then, we can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_X-\mu_Y)}{s_{M_d}}=\dfrac{0.16-0}{0.189}=\dfrac{0.16}{0.189}=0.8453

The degrees of freedom for this test are:

df=n_1+n_2-1=80+80-2=158

This test is a right-tailed test, with 158 degrees of freedom and t=0.8453, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>0.8453)=0.1996

As the P-value (0.1996) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean score μX on one-tailed hypothesis test questions is higher than the mean score μY on two-tailed hypothesis test questions .

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3 years ago
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Answer:

Hi!

Step-by-step explanation:

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Sergio [31]

Answer:

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Step-by-step explanation:

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