Let length of rectangle=x and width be y
.`. area=x*y
now new length=x+12x/10=22x/10
width=y-y/5=4y/5
now .....
new area=new length-new width=22x/10*4y/5
new area=88xy/50
The answer would be <QRZ
Since you are looking for an angle congruent to <UQR using the alternate interior angles theorem, interior suggests that the angle must be inside the parallel lines, se we can get rid of options <WRT and <TRZ since they are exterior angles
Furthermore, in the alternate interior angles theorem, the two angles must be alternate or opposite of each other which would show that the only possible answer would be <QRZ
hope this helped!
Answer:
y = 3x - 14
Step-by-step explanation:
If a line is parallel to another, it will have the same slope
So, the line's slope will be 3
Plug in the given point and the slope into y = mx + b, and solve for b
y = mx + b
-2 = 3(4) + b
-2 = 12 + b
-14 = b
Plug in the slope and b into y = mx + b
y = 3x - 14
So, the equation is y = 3x - 14
Answer:
8
Step-by-step explanation:
Let's set this up to see if we can simplify it a bit:
Notice we have 4 tens on top and 3 on bottom, so we can eliminate the bottom 3 altogether and leave just one on top. And we have 2 fives on the top and 3 on bottom, so we can eliminate the 2 on the top and leave one on the bottom. Now that looks like this:
10 divided by 5 is 2, and 2 cubed is 8
