Answer:
Rectangle 1 : length = x ; width = y
Rectangle 2 : length = kx ; width = ky
Step-by-step explanation:
Assume that x = 10; y = 5 ; k = 2
Area:
Rectangle 1 : 10 x 5 = 50
Rectangle 2 : 10(2) x 5(2) = 20 x 10 = 200
a) Yes, these triangle are similar. Because Rectangle 2 is the enlarged version of Rectangle 1.
b) Perimeter:
Rectangle 1 = 2x + 2y
Rectangle 2 = 2kx + 2ky
Rectangle 2 is k times the perimeter of Rectangle 1
Rectangle 2 = k(Rectangle 1)
2kx + 2ky = k(2x + 2y)
2kx + 2ky = 2kx + 2ky
c) Area:
Rectangle 1 = x * y
Rectangle 2 = kx * ky
For my teacher, I John Boles solved it.