Algebra 1 > * 3.10 Solve linear equations: word problems UFG
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Solving quadratic equations, it is found that he needs to charge:
1. He needs to charge $40 to break even.
2. He needs to charge $30 for a profit of $600.
<h3>What is a quadratic function?</h3>A quadratic function is given according to the following rule:
The solutions are:
In which:
The profit equation in this problem is:
P(x) = -3x² + 150x - 1200.
He breaks even when P(x) = 0, hence:
-3x² + 150x - 1200 = 0.
The coefficients are a = -3, b = 150, c = -1200, hence:
He needs to charge $40 to break even.
For a profit of $600, we have that P(x) = 600, hence:
-3x² + 150x - 1200 = 600.
-3x² + 150x - 1800 = 0.
The coefficients are a = -3, b = 150, c = -1800, hence:
He needs to charge $30 for a profit of $600.
More can be learned about quadratic equations at brainly.com/question/24737967
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