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Fantom [35]
4 years ago
8

Determine the number of units of solution 2 required to obtain the desire percent alcohol concentration of the final solution. T

hen find the amount of the final solution. Concentration solution 1 is 10%. Amount of solution for 1 is 2gal. Concentration of solution 2 is 30% what is the amount for solution 2?
Mathematics
1 answer:
KiRa [710]4 years ago
8 0

Answer:

0.66 gal.

Step-by-step explanation:

The following should apply:

C1 * V1 = C2 * V2

we have that C1 is 0.1, that C2 is 0.3 and that V1 is equal to 2 gal

replacing the values we have that:

0.1 * 2 = 0.3 * V2

reorganizing the equation we have:

V2 = 0.1 * 2 / 0.3 solving this remains 0.66.

It means that the amount of solution 2 is 0.66 gal.

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On a coordinate plane, an absolute value graph has a vertex at (10, 6).
lorasvet [3.4K]

Answer: (10, ∞)

Step-by-step explanation:

See the graph in the attached image.

4 0
2 years ago
2<br> 3(9x - 6) = 4x + 10<br> What is the value of X In the equation
andreev551 [17]

Answer:

Step-by-step explanation:

23(9x-6) = 4x +10            

207x - 138 = 4x +10

203x = 148                                                    

x = 148/203

 or  

3(9x-6) = 4x +10

27x -18 = 4x + 10

   27x - 4x = 10 + 18

          23x = 28

x= 28/23

4 0
3 years ago
You get scores of 85 and 91 on two history test.Wright and solve an inequality to find the scores you can get on your next histo
Goryan [66]
Let x = score on next test
(85+91+x)/3\geq90
x\geq94
5 0
4 years ago
Sum of all natural numbers from100to300 which are divisible by 4and 5 is​
My name is Ann [436]

If x is a number that is both divisible by 4 and 5, then

\begin{cases}x\equiv0\pmod4\\x\equiv0\pmod5\end{cases}

4 and 5 are coprime, so we can use the Chinese remainder theorem to solve this system and find that x=20n is a solution to the system, where n is any integer. Simply put, any multiple of 20 fits the bill.

Now, there are 11 numbers between 100 and 300 that are divisible by 20 (100, 120, 140, and so on). We have 20n=100 when n=5, so the sum we want to compute is

\displaystyle\sum_{n=5}^{15}20n=\boxed{2200}

4 0
3 years ago
Raw scores on a certain standardized test one year were normally distributed, with a mean of 156 and a standard deviation of 23.
s344n2d4d5 [400]

Answer:

About 220 of the students scored less than 96

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 156 and a standard deviation of 23.

This means that \mu = 156, \sigma = 23

Proportion that scored less than 96:

p-value of Z when X = 96. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{96 - 156}{23}

Z = -2.61

Z = -2.61 has a p-value of 0.00453.

About how many of the students scored less than 96?

0.00453 out of 48592.

0.00453*48592 = 220.1.

Rounding to the closest integer:

About 220 of the students scored less than 96

3 0
3 years ago
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