There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Then the numbers are 45 and 19
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Solution:</u></h3>
Given that, There are two numbers whose sum is 64.
Let the number be a and b in which a is bigger.
Then, a + b = 64 ------ eqn (1)
The larger number subtracted from 4 times the smaller number gives 31.
4 x b – a = 31
4b – a = 31 ----- eqn (2)
We have to find the numbers.
So, from eqn (2)
a = 4b – 31
Subatitute a in (1)
4b – 31 + b = 64
On solving we get
5b = 64 + 31
5b = 95
b = 19
So, b = 19, then eqn 1
a + 19 = 64
On simplification,
a = 64 – 19
a = 45
Hence, the two numbers are 45 and 19
Answer:
B!
Step-by-step explanation:
Step-by-step explanation:
20
Constant in a mathematical expression is a term whose value never changes.
The terms with x and y will vary based on the variable x and or y.
1, ___, ____, _____, _____, _____, ____, 29
29-1 = 28
28/7 = 4
1, 5, 9, 13, 17, 21, 25, 29
