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KATRIN_1 [288]
3 years ago
14

Given f(x) = x cubed - 3, find f(-2)​

Mathematics
1 answer:
lina2011 [118]3 years ago
8 0

Answer:

f(-2) = -11

Step-by-step explanation:

f(x) =x^(3)-3

We want to find f(-2) , which means x=-2

f(-2) = (-2) ^3-3

(-2)^3 = -8

f(-2) = (-8)-3

f(-2) = -11

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Which equation has the solutions x = -3 ± √3i/2 ?
Maurinko [17]

Answer:Answer is option C : [x^{2} + 3x + 3 ] =0

Note:  None of options matches with given question.

instead of "-3" , there should be "-\frac{3}{2}".

Step-by-step explanation:

Note:  None of options matches with given question.

instead of "-3" , there should be "\frac{3}{2}".  

Here, First thing you have to observe the nature of roots.

∴ x = -\frac{3}{2}+\frac{\sqrt{3}}{2}i and x = -\frac{3}{2}-\frac{\sqrt{3}}{2}

∴ [ x+(\frac{3}{2}-\frac{\sqrt{3}}{2}i) ][ x+(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [ x^{2} + x(\frac{3}{2}+\frac{\sqrt{3}}{2}i)+ x(\frac{3}{2}-\frac{\sqrt{3}}{2}i) + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [x^{2} + \frac{3}{2}x + \frac{\sqrt{3}}{2}ix + \frac{3}{2}x - \frac{\sqrt{3}}{2}ix + (3-\frac{\sqrt{3}}{2}i)(3+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{\sqrt{3}}{2}i)(\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{3}{4}) i^{2} ] =0

∴ [x^{2} + 3x + \frac{9}{4} + (\frac{3}{4}) ] =0

∴ [x^{2} + 3x + \frac{12}{4} ] =0  

∴ [x^{2} + 3x + 3 ] =0  

Thus, Answer is option C : <em>[x^{2} + 3x + 3 ] =0  </em>

6 0
3 years ago
H(x) = x2<br> j(x) = 2x2-5<br> find h(x) - j(x)
yKpoI14uk [10]

Answer:

Step-by-step explanation:

h(x) - j(x) => x^2-(2x^2-5)

The negative sign out in front of the set of parenthesis changes the signs of everything inside the parenthesis, so now we have, without parenthesis:

x^2-2x^2+5 which simplifies down to

-x^2+5

4 0
3 years ago
Why is 1/8 greater than 1/10 but less than 1/3
zzz [600]

because the bigger the bottom or left number is the smaller the value unless t was like 10/10 that's bigger than them all
6 0
2 years ago
Find the value of x. help please
Anni [7]
To find x just set this = to 180 bc is a supp angle so 58+x=180 and then subtract 58 from both sides 180-58=122 rewrite x=122
Hope this helps have a nice day!
8 0
3 years ago
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likoan [24]

Answer:

Step-by-step explanation:

In order to find the center and the radius of this circle, you have to complete the square on it. And only for the x-terms, because the y term is squared and there is no other y term. We'll get to that in a second.

Take half the linear x-term, square it and add it to both sides. Our linear term is 10. Half of 10 is 5, and 5 squared is 25. We add 25 to both sides:

The reason we do this is to create a perfect square binomial inside that set of parenthesis. Simplifying the right side as well gives us:

This tells us that the center is (-5, 0). Remember when I said we would get back to the y terms? Because there was only a y-squared and no other y terms, that is the same as writing the equation as

The radius is the square root of the constant. So the radius is 6.

D is the graph you want.

3 0
3 years ago
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