Plz help me Thx so much
2 answers:
You might be interested in
Answer:
The answer is below
Step-by-step explanation:
The standard form of the equation of an ellipse with major axis on the y axis is given as:
Where (h, k) is the center of the ellipse, (h, k ± a) is the major axis, (h ± b, k) is the minor axis, (h, k ± c) is the foci and c² = a² - b²
Since the minor axis is at (37,0) and (-37,0), hence k = 0, h = 0 and b = 37
Also, the foci is at (0,5) and (0, -5), therefore c = 5
Using c² = a² - b²:
5² = a² - 37²
a² = 37² + 5² = 1369 + 25
a² = 1394
Therefore the equation of the ellipse is:
The complete question in the attached figure
we know that
length side AB=8 units
length side DE=4 units
[ABC]=[DEF]*[scale factor]
then
[scale factor ]=[ABC]/[DEF]---------> 8/4--------> 2
the answer is
the scale factor for a dilation image of DEF to obtain ABC is 2
we know that
length side AB=8 units
length side DE=4 units
[ABC]=[DEF]*[scale factor]
then
[scale factor ]=[ABC]/[DEF]---------> 8/4--------> 2
the answer is
the scale factor for a dilation image of DEF to obtain ABC is 2
The valid conclusions for the manager based on the considered test is given by: Option
<h3>When do we perform one sample z-test?</h3>One sample z-test is performed if the sample size is large enough (n > 30) and we want to know if the sample comes from the specific population.
For this case, we're specified that:
- Population mean =
= $150
- Population standard deviation =
= $30.20
- Sample mean =
= $160
- Sample size = n = 40 > 30
- Level of significance =
= 2.5% = 0.025
- We want to determine if the average customer spends more in his store than the national average.
Forming hypotheses:
- Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get:
- Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically
where is the hypothesized population mean of the money his customer spends in his store.
The z-test statistic we get is:
The test is single tailed, (right tailed).
The critical value of z at level of significance 0.025 is 1.96
Since we've got 2.904 > 1.96, so we reject the null hypothesis.
(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).
Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.
Learn more about one-sample z-test here: