Answer:
The approximate probability that 10 squared centimeters of dust contains more than 10110 particles is 0.1357
Step-by-step explanation:
For a sample of 10 sqaured centimeters of dust, the total amount of asbestos particles has a Poisson distribution with a mean of 1000/1 * 10 = 10000.
We will approximate this probability to a normal distribution. The variance is also 10000 (because it is poisson), therefore the standard deviation is √10000 = 100. Lets call X the distribution, and W its standarization, given by
We have
Where 
is the cummulative distribution function of a standard normal distribution. The values of are well known and they can be found in the attached file.
We conclude that the approximate probability that 10 squared centimeters of dust contains more than 10110 particles is 0.1357.
A(n)=4+4(n-1)
a(n)=4+4n-4
a(n)=4n
76=4n
n=19
The sum of any arithmetic sequence (series are infinite) is:
(a+a(n))(n/2)
The average of the first and last terms times the number of terms, in this case we found that n=19 so:
19(4+76)/2=760
Well, since there is no image I am unable to say the exact volume. But here is the volume formula-
V=L times W times H
*V=volume W=width H=height
and you don't actually have to write times you can do the symbol.
Example- if I had a rectangular prism of the width being 5 cubes, the length 8 cubes, and the height 7 cubes(following how many gallons are in a cube 7.5) I would the use my formula. V=LWH- 8 times 7= 56 56 times 5=280 280 times 7.5= 2100
V=2100 (that is your answer reply If you didn't mean the volume or you don't get it)
The answer is 296 because you do 74*400 which equals 29,600 then divide by 100 and get 296.
Answer:
1/2
Step-by-step explanation:
7/10 - 1/5
=> 7/10 - 1*2/5*2
=> 7/10 - 2/10
=> (7-2)/10
=> 5/10
=> 1/2
