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podryga [215]
3 years ago
5

Iam stuck on this quiz and I need help!!

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
3 0

Answer:

I think it is 3?

Step-by-step explanation:

3,  -2 ≤ 0

-5,  0 < -2 ≤ 5

3, -2 > 5

The second two lines do not hold true, as -2 is less than 0 and 5, not greater. The only that is true is the first one, but I am not sure that is how you do it.1

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Diana invested $3000 in a savings account for 3 years. She earned $450 in interest over that time period. What interest rate did
shutvik [7]
Easy 450=3000*3*r R=450/9000 R=0.05*100 R=5%
5 0
3 years ago
-X-5y + z = 17
grin007 [14]

Answer:

x = -1 , y = -4 , z = -4

Step-by-step explanation:

Solve the following system:

{-x - 5 y + z = 17 | (equation 1)

-5 x - 5 y + 5 z = 5 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Swap equation 1 with equation 2:

{-(5 x) - 5 y + 5 z = 5 | (equation 1)

-x - 5 y + z = 17 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Subtract 1/5 × (equation 1) from equation 2:

{-(5 x) - 5 y + 5 z = 5 | (equation 1)

0 x - 4 y+0 z = 16 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Divide equation 1 by 5:

{-x - y + z = 1 | (equation 1)

0 x - 4 y+0 z = 16 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Divide equation 2 by 4:

{-x - y + z = 1 | (equation 1)

0 x - y+0 z = 4 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Add 2 × (equation 1) to equation 3:

{-x - y + z = 1 | (equation 1)

0 x - y+0 z = 4 | (equation 2)

0 x+3 y - z = -8 | (equation 3)

Swap equation 2 with equation 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x - y+0 z = 4 | (equation 3)

Add 1/3 × (equation 2) to equation 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y - z/3 = 4/3 | (equation 3)

Multiply equation 3 by 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y - z = 4 | (equation 3)

Multiply equation 3 by -1:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Add equation 3 to equation 2:

{-x - y + z = 1 | (equation 1)

0 x+3 y+0 z = -12 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Divide equation 2 by 3:

{-x - y + z = 1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Add equation 2 to equation 1:

{-x + 0 y+z = -3 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Subtract equation 3 from equation 1:

{-x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Multiply equation 1 by -1:

{x+0 y+0 z = -1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Collect results:

Answer: {x = -1 , y = -4 , z = -4

8 0
3 years ago
Bret needs 450 packs of paper for next week. He has 284 packs of paper. How many more packs of paper dose bret need?
gulaghasi [49]

Answer:

166 packs

Step-by-step explanation:

Data obtained from the question include:

Total pack of paper needed by Bret 450 packs

Bret currently has = 284 packs

The remaining packs of paper needed by Bret = 450 — 284 = 166 packs

5 0
3 years ago
Read 2 more answers
Anyone know the answer ???
mafiozo [28]
Hello!

Since the angles are same side alternate angles they are equal to each other

60 - 2x = 70 - 4x

We solve this algebraically

Add 4x to both sides

60 + 2x = 70

Subtract 60 from both sides

2x = 10

divide both sides by 2

x = 5

Hope this helps!
6 0
3 years ago
A new cruise ship line has just launched 3 new​ ships: the Pacific​ Paradise, the Caribbean​ Paradise, and the Mediterranean Par
topjm [15]
Let the number of deluxe that Pacific has be x
the number that Caribbean has will be (x+18)
the number that Mediterranean has will be (3x-25)
total b=number of deluxe in the 3 ships will be:
x+(x+18)+(3x-25)
5x-7=928
5x=928+7
x=935/5
x=187
Hence the Pacific has 187, Caribbean has 187+18=205, Mediterranean has (3*187-25)
=534 
6 0
3 years ago
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