If the matrix is of 2 by 2 then we can find the determinant of the matrix.
Then (ad - bc ) gives you the determinant of the matrix.
For example,
= (2)(-2) - (1)(4)
= - 4 - 4
= -8
Step-by-step explanation:
you did not even try a calculator to find the result ?
64 is 8×8 or 8².
so, sqrt(64) = 8.
similarly for 4 :
4 is 2×2 or 2².
so, sqrt(4) = 2
so,
sqrt(64)/ sqrt(4) = 8 / 2 = 4
so, d. is the right answer.
The perpendicular line to x-6y=2, and passing through (2, 4) is y=-6x+16
<span>There is a 20% (or 20/100chance) it will rain on Thursday and there is a 40% (or 40/100) chance it will rain on Friday. In order to find out the probability of it raining both days, we need to multiply these two values. (40/100)(20/100)= 800/10,000= 0.08. We move the decimal over two places to get a percent, so we get an 8% chance it will rain on both Thursday and Friday.</span>
Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
