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otez555 [7]
3 years ago
12

Solve each quadratic equation by factoring and using the zero product property.

Mathematics
2 answers:
zepelin [54]3 years ago
8 0

Answer:

x  = 5 or x  = 6

Step-by-step explanation:

Given equation is :

x²-8x+30   = 3x

adding -3x to both sides of above equation, we get

x²-8x+30-3x  = 3x-3x

add like terms

x²-11x+30  = 0

we solve this equation by factoring.

split the middle term so that the product of two numbers should be 30 and the sum is -11.

x²-6x-5x+30  = 0

make two groups

x(x-6)-5(x-6)  = 0

take (x-6) as common

(x-6)(x-5)  = 0

Applying Zero-Product Property to above equation,we get

x-6  = 0 or x-5  = 0

first solve x-6  = 0

adding 6 to both sides of above equation,we get

x-6+6  = 0+6

x+0  = 6

x  = 6

secondly, solve this x-5 = 0

adding 5 to above equation , we get

x-5+5  = 0+5

x +0  = 5

x  = 5

Hence, the solution of x²-8x+30  = 3x  is {6,5}.

Iteru [2.4K]3 years ago
7 0

Answer:

x=5                            x=6

Step-by-step explanation:

x^2 - 8x + 30 = 3x

Subtract 3x from each side

x^2 - 8x-3x + 30 = 3x-3x

x^2 - 11x + 30 = 0

What 2 numbers multiply to 30 and add to -11

-5*-6 = 30

-5+-6 = -11

(x-5) (x-6) =0

Using the zero product property

x-5 = 0  and x-6 =0

x-5+5 =0+5   and x-6+6 =0+6

x=5                            x=6

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<h3>What is Box and Whisker plots?</h3>

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        The upper extreme is the highest value, which is 89.

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        The upper quartile is 86 and the lower quartile is 62.

  • Range of the data be,

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From the second figure, write all the values where dark point is drawn

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        The upper extreme is the highest value, which is 96.

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       The upper quartile is 89 and the lower quartile is 62.

  • Range of the data be,

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From the above discussion,  

  • The First class have less upper extreme value than the second class.
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The comparision of the two classes on the basis of extremes, quartile, median, range is concluded above.

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