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MaRussiya [10]
3 years ago
11

Simplify each of the following expressions.

Mathematics
1 answer:
Advocard [28]3 years ago
4 0
The answer to the question

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The volume of this cylinder is 175pi cubic units. What is the volume of a cone that has the same base area and the same height?
SCORPION-xisa [38]

Answer:

79,168.135

Step-by-step explanation:

6 0
2 years ago
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What is the average rate of change of the function over the interval x = 0 to x = 8?
salantis [7]
Ans:  The average rate of change of function = \frac{1}{102} (in fraction)

Explanation:
The average rate of change of function  = \frac{f(b) - f(a)}{b - a}

Where
b = 8 (x's upper bound)
a = 0 (x's lower bound)

f(b) = f(8) =  \frac{2*8-2}{5*8-6} =  \frac{7}{17} \\ f(a) = f(0) =  \frac{2*0-2}{5*0-6} =  \frac{1}{3} \\  \frac{f(b)  - f(a)}{b-a} =  \frac{ \frac{7}{17} -  \frac{1}{3}}{8} =  \frac{1}{102}

Hence the average rate of change of function = \frac{1}{102} (in fraction)
5 0
3 years ago
Y>1 and y>x on a graph
zlopas [31]

So,

y>1\wedge y>x

1. Graph each inequality separately.

2. Choose a test point to determine which side of the line needs to be shaded.

3. The solution to the system will be the area where the shadings from each inequality overlap one another (purple area)

As for the system of inequalities we say it's unbounded.

3 0
3 years ago
Is 4/2 + 5/2 a rational or irrational number
sesenic [268]
As both 4/2 and 5/2 are rational Numbers and Sum of rationals is a Rational Number.
Therefore, 9/2 is a Rational Number.
6 0
2 years ago
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The square root of the quotient of a number n and 3 is equal to the square root of 4 less than the number. Which of the followin
Lisa [10]

Answer:

6

Step-by-step explanation: You can set up the equation: \sqrt{\frac{n}{3} } = \sqrt{n-4} You square both sides to cancel out the squares which leaves you with \frac{n}{3} = n - 4. Then you just solve as normal which ends you up with an answer of 6. You can check this by plugging 6 back into the equation and see that you end up with \sqrt{2} on both sides.

4 0
2 years ago
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