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hichkok12 [17]
3 years ago
11

READ No link or bot and answer the question I give Brainliest to the best answer

Mathematics
1 answer:
emmainna [20.7K]3 years ago
4 0

Step-by-step explanation:

This a very nice speak about mathematic

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Eli invested $ 330 $330 in an account in the year 1999, and the value has been growing exponentially at a constant rate. The val
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The value of the account in the year 2009 will be $682.

Step-by-step explanation:

The acount's balance, in t years after 1999, can be modeled by the following equation.

A(t) = Pe^{rt}

In which A(t) is the amount after t years, P is the initial money deposited, and r is the rate of interest.

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This means that P = 330

$590 in the year 2007

2007 is 8 years after 1999, so P(8) = 590.

We use this to find r.

A(t) = Pe^{rt}

590 = 330e^{8r}

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Applying ln to both sides:

\ln{e^{8r}} = \ln{1.79}

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Determine the value of the account, to the nearest dollar, in the year 2009.

2009 is 10 years after 1999, so this is A(10).

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The value of the account in the year 2009 will be $682.

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