D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
Answer:
A' (3, 8 )
Step-by-step explanation:
Applying the translation rule to A (1, 3 )
A (1, 3 ) → A' (1 + 2, 3 + 5 ) → A' (3, 8 )
Answer:
D) 9 postcards with 2 shells each.
Explanation:
9 x 2 = 18
Therefore, 9 postcards with 2 shells each is the correct answer.
Please give brainliest.
Answer:
1.

2.

3.

Step-by-step explanation:
1. The given polynomial is

We need to factor the second part to get:

We factor y-5 to obtain:

2. We have

We again factor -1 from the second part to get:

We now factor x-y to get:


3. We have

We factor negative 1 from the first part to get

We now factor b-3 to get:

We now simplify to get:

8 units that Is the answer