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Slav-nsk [51]
4 years ago
10

Subtract the following the Hex numbers: 67h 2Ah Result is =

Computers and Technology
1 answer:
-BARSIC- [3]4 years ago
4 0

Answer:

3D ( in hexadecimal )

Explanation:

Converting the given hexadecimal numbers to decimal:

 67 (HEX) = 16*6 + 7 = 103 (Decimal)

 2A (HEX) = 2*16 + 10 = 42 (Decimal)

Subtracting the two numbers: 103 - 42 = 61 (Decimal)

Converting the result to Hexadecimal format:

61 = 16* 3 + 13

13 corresponds to D in hexadecimal.

So result in hex is 3D.

To summarize, the subtraction result for the two given hexadecimal numbers is 61 in decimal format or 3D in hexadecimal.

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b. Synchronous replication

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The unique reason why assembler language is preferred to high level language is that  It is said to be memory efficient and it is one that requires less memory.

<h3>Why is assembly language better than other kinds of high level?</h3>

It implies means that the programs that one uses to write via the use of high-level languages can be run easily on any processor that is known to be independent of its type.

Note that it is one that has a lot of  better accuracy and an assembly language is one that carries out a lot of better functions than any high-level language, in all.

Note also that the advantages of assembly language over high-level language is in terms of its Performance and accuracy as it is better than high-level language.

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Given parameters b and h which stand for the base and the height of an isosceles triangle (i.e., a triangle that has two equal s
schepotkina [342]

Answer:

The area of the triangle is calculated as thus:

Area = 0.5 * b * h

To calculate the perimeter of the triangle, the measurement of the slant height has to be derived;

Let s represent the slant height;

Dividing the triangle into 2 gives a right angled triangle;

The slant height, s is calculated using Pythagoras theorem as thus

s = \sqrt{b^2 + h^2}

The perimeter of the triangle is then calculated as thus;

Perimeter = s + s + b

Perimeter = \sqrt{b^2 + h^2} + \sqrt{b^2 + h^2} +b

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For the volume of the cone,

when the triangle is spin, the base of the triangle forms the diameter of the cone;

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Base on the above illustrations, the program is as follows;

#include<iostream>

#include<cmath>

using namespace std;

void CalcArea(double b, double h)

{

//Calculate Area

double Area = 0.5 * b * h;

//Print Area

cout<<"Area = "<<Area<<endl;

}

void CalcPerimeter(double b, double h)

{

//Calculate Perimeter

double Perimeter = 2 * sqrt(pow(h,2)+pow((0.5 * b),2)) + b;

//Print Perimeter

cout<<"Perimeter = "<<Perimeter<<endl;

}

void CalcVolume(double b, double h)

{

//Calculate Volume

double Volume = (1.0/3.0) * (22.0/7.0) * pow((0.5 * b),2) * h;

//Print Volume

cout<<"Volume = "<<Volume<<endl;

}

int main()

{

double b, h;

//Prompt User for input

cout<<"Base: ";

cin>>b;

cout<<"Height: ";

cin>>h;

//Call CalcVolume function

CalcVolume(b,h);

//Call CalcArea function

CalcArea(b,h);

//Call CalcPerimeter function

CalcPerimeter(b,h);

 

return 0;

}

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3 years ago
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