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Anon25 [30]
2 years ago
10

Listed three functions tht are ysed in a spreadsheet​

Computers and Technology
1 answer:
Karo-lina-s [1.5K]2 years ago
5 0

Answer:

The sum function

The count function

The trim function etc.

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Why does the media play such an important role in our personal freedom? Select 3 options.
Helga [31]

Answer:

It promotes self-expression

It holds the government accountable

It keeps us informed

Explanation:

I got them right Ed

7 0
2 years ago
Write a java program to print the following series: <br>1 5 9 13 17...n terms​
andrew11 [14]

Answer:

In Java:

import java.util.*;

public class Main{

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

int n;

System.out.print("Max of series: ");

n = input.nextInt();

for(int i = 1; i<=n;i+=4){

    System.out.print(i+" ");

}

}

}

Explanation:

This declares n as integer. n represents the maximum of the series

int n;

This prompts the user for maximum of the series

System.out.print("Max of series: ");

This gets user input for n

n = input.nextInt();

The following iteration prints from 1 to n, with an increment of 4

<em> for(int i = 1; i<=n;i+=4){</em>

<em>     System.out.print(i+" ");</em>

<em>}</em>

6 0
3 years ago
Read 2 more answers
Can someone tell me why this keeps exiting no matter what move and how I can fix it I honestly hate this class... you guys can h
velikii [3]

Answer:

Something like this?

The only requirement this doesn't exactly hit is moving the user to the "exit" room. It doesn't make use of that entry in the dictionary. However, this is the best way of doing it to avoid multiple "if" statements.

7 0
2 years ago
A _______________ is a field that contains data unique to a record.
Andru [333]

A primary key is a field that contains data unique to a record

8 0
3 years ago
A computer’s memory is composed of 8K words of 32 bits each. How many bits are required for memory addressing if the smallest ad
victus00 [196]

Answer:

The minimum number of bits necessary to address 8K words is 13.

Explanation:

You have the number of words to address that is 8000 words, a word is the smallest addressable memory unit.  

8000 words can be addressed with 2^{n}  units. Now you have to find the value of n that approximates to the number of words.  

2^2=4\\2^4=16\\2^7=128\\2^{10}=1024\\2^{12}=4096\\2^{13}=8192

So you can see that 13 bits are needed to address 8K words.

7 0
3 years ago
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