Even numbers are numbers whigh are divisible by 2. Therefore, the first even number is 2. A pseudocode which adds the first 100 even numbers can be written thus :
counter = 0
sum = 0
interval = 2
while counter < 100 :
sum = sum + interval
interval += 2
counter +=1
print(sum)
- A counter takes count of the number of values summed
- Initializes a variable which holds the sum of even values
- Since even numbers are divisible by 2; every factor ; increase every added value by 2
- The program ends once counter is 100
Learn more : brainly.com/question/25327166
Answer:
its not an assembly line
Explanation:
assembly lines have ppl who aren't experts and are taught to only do one simple part of a much much bigger thing
I would honestly say that there are a few available tools that Carrie can use, but the best tool is the inbuilt Windows Powershell. As Powershell continues to extend its purpose and usefulness, Microsoft, on the other hand, continues to use Powershell's capability to develop more cmdlets for products like Windows Servers. Everything that can be done in a GUI environment can be done in Powershell. Carrie should be able to use Powershell to run things more efficiently from the command line without stepping a foot on the physical server. She will only need to access the server from her desk remotely, run a few commands, and that is it. Powershell command line is so powerful; it carries with it every troubleshooting pack that you can think about.
Yes the ansewer is c bc you can look it up!
Answer:
#include <bits/stdc++.h>
using namespace std;
bool isPalindrome(string str)
{
char a,b;
int length = str.length();
for (int i = 0; i < length / 2; i++)
{
a=tolower(str[i]);//Converting both first characters to lowercase..
b=tolower(str[length-1-i]);
if (b != a )
return false;
}
return true;
}
int main() {
string t1;
cin>>t1;
if(isPalindrome(t1))
cout<<"The string is Palindrome"<<endl;
else
cout<<"The string is not Palindrome"<<endl;
return 0;
}
Output:-
Enter the string
madam
The string is Palindrome
Enter the string
abba
The string is Palindrome
Enter the string
22
The string is Palindrome
Enter the string
67876
The string is Palindrome
Enter the string
444244
The string is not Palindrome
Explanation:
To ignore the cases of uppercase and lower case i have converted every character to lowercase then checking each character.You can convert to uppercase also that will also work.
