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Veronika [31]
3 years ago
8

Ivan made a scaled copy of the following triangle. He used a scale factor less than 1

Mathematics
2 answers:
Elan Coil [88]3 years ago
5 0

Answer: hi can u help me. i have this same question. what were the answers?

Step-by-step explanation:

Yuliya22 [10]3 years ago
4 0

Answer:

(4.5 units) (2 units) (1/2 units)

Step-by-step explanation:

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A billboard designer has decided that a sign should have 4-ft margins at the top and bottom and 1-ft margins on the left and rig
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An equation is formed of two equal expressions. The value of x that maximizes the area of the printed region of the billboard is 9.655 ft.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Given x is the left-right width of the billboard and y is the height of the billboard. Therefore,

The total area of the billboard, A= x·y

The total printed area of the billboard, A_p=(x-2)(y-8)

Given in problem that the area of the billboard is 3600 ft².

x·y = 3600

y = (3600)/x

Substituting the value of y in the equation of the total printed area of the billboard,

A_p = (x-2)(\dfrac{3600}{x}-8)\\\\A_p = 3600 -8x -\dfrac{7200}{x} + 16\\\\A_p =3616-8x - \dfrac{7200}{x}

Now, the value of x is needed to be minimum, therefore, differentiating the given function,

\dfrac{d}{dx}A_p =\dfrac{d}{dx}3616-8x - \dfrac{7200}{x}\\\\\dfrac{d}{dx}A_p =-8 - \dfrac{7200}{x^2}

Equate the differentiated function with 0,

0=-8x - \dfrac{7200}{x^2}\\\\8x = - \dfrac{7200}{x^2}\\\\x^3 = 900\\\\x = 9.655 ft.

Hence, the value of x that maximizes the area of the printed region of the billboard is 9.655 ft.

Learn more about Equation:

brainly.com/question/2263981

#SPJ1

4 0
2 years ago
8 cm<br> 4 cm<br> 3cm. <br> 6cm <br><br> What is the area of the figure in square centimeters?
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Hii :))

\tt \: ( \frac{18}{ - 2} ) ^{2}  \\   \tt \: =  (-  \frac{18}{2} ) ^{2}  \\  \tt =  \frac{-18 \times -18}{-2 \times -2}  \\  =    \tt  \frac{324}{4}  \\ = \boxed{\tt\:81}

﹋﹋﹋﹋﹋﹋﹋﹋﹋﹋

\overbrace{ \underbrace{ \sf \: \infty  \:  Carry \: on \: Learning \:  \infty }}

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