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leonid [27]
3 years ago
7

Someone pls help the girl out ASAP I am trying to go to bed I need help with these two questions pls help me!!!:)

Mathematics
1 answer:
solniwko [45]3 years ago
7 0

Answer:

4.) $795.16

5.) C

Step-by-step explanation:

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Please help with this
N76 [4]
VWX\cong KLJ means that the triangles are congruent, that is exactly identical.

The order of letters is very important. Form the given congruence we can write the following ratio:

\frac{VW}{KL} = \frac{WX}{LJ} = \frac{VX}{KJ} =1

(notice that we do not mix the order: the first 2 letters of VWX are compared to the first 2 letters of KLJ and so on)

the ratio is one because the corresponding sides are equal.

\frac{VW}{KL}=1\\\\ \frac{2z-1}{z+2}=1\\\\2z-1=z+2\\\\2z-z=2+1\\\\z=3

|VW|=2z-1=2.3-1=6-1=5


Answer: 5 units


8 0
3 years ago
After simplifying, how many terms does the expression 4y-6+y2-9 contain?​
Alex73 [517]

Answer:

There are three terms in the simplified expression.

Step-by-step explanation:

We have to simplify the expression and have to count the number of terms that the expression has.

The expression is 4y - 6 + y² - 9

= 4y + y² - 6 - 9

= y² + 4y - 15

Therefore, there are three terms in the simplified expression, one for y² term, another is y term and the constant term. (Answer)

8 0
3 years ago
Read 2 more answers
State if the two triangles are congruent. if they are state how you know.
nlexa [21]
1) The triangles are congruent by SSS.

The two tick marks indicate two pairs of congruent sides; it is evident that the third side is congruent by the way the diagram is drawn - the bases of the triangles are together and appear to be the same length.

2) The triangles are congruent by SAS.

The two pairs of tick marks indicate congruent sides, and their included angles are congruent because they are vertical angles, and vertical angles are always congruent.
5 0
3 years ago
ASAP !!
brilliants [131]

Answer:

17

Step-by-step explanation:

8 0
3 years ago
Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio
JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

Initial =1\ million

6\ years\ later = 500,000

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

\frac{dA}{dt} = kA

Where k represents the constant of proportionality

\frac{dA}{dt} = kA

Multiply both sides by dt/A

\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}

\frac{dA}{A}  = k\ dt

Integrate both sides

\int\ {\frac{dA}{A}  = \int\ {k\ dt}

ln\ A = kt + lnC

Make A, the subject

A = Ce^{kt}

t = 0\ when\ A =1\ million i.e. At initial

So, we have:

A = Ce^{kt}

1000000 = Ce^{k*0}

1000000 = Ce^{0}

1000000 = C*1

1000000 = C

C =1000000

Substitute C =1000000 in A = Ce^{kt}

A = 1000000e^{kt}

To solve for k;

6\ years\ later = 500,000

i.e.

t = 6\ A = 500000

So:

500000= 1000000e^{k*6}

Divide both sides by 1000000

0.5= e^{k*6}

Take natural logarithm (ln) of both sides

ln(0.5) = ln(e^{k*6})

ln(0.5) = k*6

Solve for k

k = \frac{ln(0.5)}{6}

k = \frac{-0.693}{6}

k = -0.1155

Recall that:

\frac{dA}{dt} = kA

Where

\frac{dA}{dt} = Rate

So, when

A = 600000

The rate is:

\frac{dA}{dt} = -0.1155 * 600000

\frac{dA}{dt} = -69300

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0
2 years ago
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