this isnt written the correct way in order for someone to solve it
answer:
the answer is -3 and 8
Step-by-step explanation:
we will place -3 in the equation
(x+3)(x-x)=0
(-3+3)=0 (because -3+3 will cut down together)
we will place two 8(eights) in the equation
(8-8)=0
final answer is
(0)(0)=0
so -3 and 8 fits well in the equation
Answer:
because the square root of 10 is an irrational number, and only rational numbers are integers. integers are whole numbers and have no fractions or decimels... hope it helps
Answer:
The expression is ![f (x) = \frac{x}{3} - 6](https://tex.z-dn.net/?f=f%20%28x%29%20%3D%20%5Cfrac%7Bx%7D%7B3%7D%20-%206)
Step-by-step explanation:
<u><em> Step(i):-</em></u>
Given variable start with 'x'
The variable 'x' is divided by '3' so ![\frac{x}{3}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B3%7D)
<u><em>Step(ii):</em></u>-
The variable 'x' is divided by '3' so
and after that subtract '6'
Then the expression
![f (x) = \frac{x}{3} - 6](https://tex.z-dn.net/?f=f%20%28x%29%20%3D%20%5Cfrac%7Bx%7D%7B3%7D%20-%206)
Answer:
is consider prime (also known as not factorable over the rationals)
Step-by-step explanation:
is consider prime.
comparing to
gives you
.
Since a=1, all you have to do is find two numbers that multiply to be -10 and add up to be -7.
Here are all the integer pairs that multiply to be -10:
-1(10)
1(-10)
2(-5)
-2(5)
Now you will see none of those pairs adds to be -7:
-1+10=9
1+(-10)=-9
2+(-5)=-3
-2+5=3
So this is not factorable over the real numbers.
Now if you had something like
, that would be a different story. You can find two numbers that multiply to be 10 and add up to be -7. Those numbers are -2 and -5 since -2(-5)=10 and -2+(-5)=-7. So the factored form of
is
.