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3 years ago

How to solve -3a + 52a

2 answers:

6 0

Well it really depends of what a is equal to. But here it is with parenthesis;
( -3 x a ) + (52 x a) so you are adding -3 x a to 52 x a. If you know what a is I could give you the final answer.

alisha [4.7K]3 years ago

5 0

Simple...

you have: -3a+52a

Simply add--->>

49a

Thus, your answer.

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Five years ago, Mark was twice as old as Max. In three years, Max's age will be 2/3 that of Mark. What is the sum of their ages

Marrrta [24]

Answer:

4years

Step-by-step explanation:

Let the present age of Mark be x

Let the present age of Max be y

Five years ago

Mark = x-5

Max = y - 5

If mark was twice as old as Max, then;

x - 5 = 2(y-5)

x-5 = 2y - 10

x-2y = -10+5

x - 2y = -5 ... 1

In three years,

mark = x+3

Max = y+3

Now if Max's age will be 2/3 that of Mark, then;

x+3 = 2/3(y+3)

3(x+3) = 2(y+3)

3x + 9 = 2y+6

3x-2y = -3 .... 2

Solve 1 and 2 simultaneously

x - 2y = -5 ... 1

3x-2y = -3 .... 2

From 1: x = -5 + 2y

Substitute into 2:

3(-5+2y) - 2y = -3

-15 + 6y - 2y = -3

-15 + 4y = -3

4y = -3 + 15

4y = 12

y = 3

Recall thet x = -5+2y

x = -5+2(3)

x = -5 + 6

x = 1

The sum of their ages will be x+y

x+y = 1+3

x+y = 4

Hence the sum of their ages now is 4years

3 0

3 years ago

A technician is installing two bundles of cables for an online system. Bundle A is 1

Mila [183]

Answer:

Answer D: 8.7 cm

Step-by-step explanation:

First compare the actual diameters of both cables to find out which one is larger. If we write both diameters in fraction form (as they are given), we need to have them expressed with the same denominator for a straight forward comparison:

Bundle A: $1\frac{3}{8} =1+\frac{3}{8} = \frac{8}{8} +\frac{3}{8} =\frac{11}{8}$

Bundle B: $2\frac{3}{4} =2+\frac{3}{4}=\frac{8}{4} +\frac{3}{4}=\frac{11}{4}$

So we multiply this last fraction by 2 in numerator and denominator to obtain the same denominator as for Bundle A without actually changing its numerical value: $\frac{11}{4} = \frac{22}{8}$