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sladkih [1.3K]
3 years ago
9

Express the equilibrium constant for the following reaction.P4O10(s) ↔ P4(s) + 5 O2(g)K = [P4][O2]^5/[P4O10]K = [O2]^5K = [P4O10

]/[P4][O2]^1/5K = [O2]^-5K = [P4O10]/[P4][O2]^5
Chemistry
1 answer:
Alex17521 [72]3 years ago
7 0

Answer : The correct expression for equilibrium constant will be, K=[O_2]^5

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

P_4O_{10}(s)\rightleftharpoons P_4(s)+5O_2(g)

The expression of K will be,

K=[O_2]^5

Therefore, the correct expression for equilibrium constant will be, K=[O_2]^5

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3 years ago
A solution is prepared by dissolving 38.6 g sucrose (C12H22O11) in 495 g of water. Determine the mole fraction of sucrose if the
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x_{suc}=0.00406

Explanation:

Hello!

In this case, since the mole fraction relates the moles of solute and the moles of solution, and for sucrose it is:

x_{suc}=\frac{n_{suc}}{n_{suc}+n_{water}}

Whereas we need to compute the moles of both sucrose and water based on their molar masses (342.3 and 18.02 respectively) as shown below:

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