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gayaneshka [121]
3 years ago
13

Analyze the following chemical combinationsa) MgOb)CaCl2c) Na2O​

Chemistry
1 answer:
Rashid [163]3 years ago
8 0
The answer is B for sure
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What may be the most important tool to use for collecting data when conducting an investigation into how thermal energy affects
Anna11 [10]

Answer:

thermometer

Explanation:

The most important tool to use when collecting data relating to how thermal energy affects metals would be <u>the thermometer.</u>

The thermometer is an instrument used to measure temperatures and the temperature of a body is a measure of the amount of thermal energy present in the body.

<em>In order to obtain data relating to how thermal energy affects metals, the most important variable to take note of would be the thermal energy of the metals and this can only be done by the thermometer.</em>

5 0
2 years ago
When do we classify a disease as epidemic
djyliett [7]

Explanation:

An epidemic (from Greek ἐπί epi "upon or above" and δῆμος demos "people") is the rapid spread of disease to a large number of people in a given population within a short period of time.

3 0
3 years ago
Read 2 more answers
Determina el pH del café cuya concentración de H+ es de 0.00001M
lara31 [8.8K]

Answer:

5

Explanation:

Given parameters:

Hydrogen ion concentration  =  0.00001M

Unknown:

pH of the solution =?

Solution:

The pH is used to estimate the degree of acidity or alkalinity of a solution. To solve for pH of any solution, we use the expression below;

          pH  = -log [H⁺]

[H⁺] is the hydrogen ion concentration

        pH  = -log (1 x 10⁻⁵)

      pH = -(-5) = 5

4 0
3 years ago
Assuming all volume measurements are made at the same temperature and pressure, how many liters of oxygen gas would it take to r
EleoNora [17]
2H2 (g) + O2 (g) -->2H2 O(g)
mole ratio of H2:O2=2:1
7.25/2=3.625
3 0
3 years ago
How many bromine atoms are present in 37.9 g of CH2Br2?
VARVARA [1.3K]

Answer:

The answer to your question is: 6.55 x 10 ²³ atoms of Br

Explanation:

CH2Br2 = 37.9 g

MW CH2Br2 = (12 x 1) + (2 x 1) + (80 x 2) = 174 g

                   174 g of CH2Br2 ------------------  160 g of Br2

                   37.9 g of CH2Br2   ---------------     x

                x = 37.9 x 160/174 = 34.85 g of Br

                      1 mol of Br -----------------   160 g Br2

                         x              ----------------    174 g Be2

               x = 174 x 1 /160 = 1.088 mol of Br2

                1 mol of Br -----------------  6.023 x 10 ²³ atoms

            1.088 mol of Br -------------    x

                    x = 1.088 x 6.023 x 10 ²³ / 1 = 6.55 x 10 ²³ atoms

4 0
2 years ago
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